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Multiple Choice
In a monohybrid cross, how many different genotypes are possible from the self-fertilization of a plant with genotype aabbcc?
A
1
B
6
C
3
D
2
Verified step by step guidance
1
Identify the genotype of the plant: aabbcc. This means the plant is homozygous recessive for three different genes (a, b, and c).
Understand that self-fertilization means the plant will cross with itself, so the gametes produced will carry the alleles from this genotype.
Determine the possible gametes produced by the plant. Since the plant is homozygous recessive for all three genes, it can only produce one type of gamete: abc.
Set up the Punnett square for the self-cross using the gametes. Since only one type of gamete (abc) is produced, the cross is abc × abc.
Conclude that only one genotype (aabbcc) is possible in the offspring because both parents contribute the same alleles.