Multiple Choice
Why don't alleles from linked genes assort independently if no crossing over occurs during meiosis?
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3. Extensions to Mendelian Inheritance
Understanding Independent Assortment
Multiple Choice
In a population where the frequency of the recessive allele (q) is 0.3, what percentage of individuals are expected to be heterozygous according to Hardy-Weinberg equilibrium?
A
21%
B
9%
C
49%
D
42%
Verified step by step guidance1
Recall that according to the Hardy-Weinberg equilibrium, the allele frequencies are represented as \(p\) for the dominant allele and \(q\) for the recessive allele, where \(p + q = 1\).
Given the frequency of the recessive allele \(q = 0.3\), calculate the frequency of the dominant allele \(p\) using the equation \(p = 1 - q\).
The frequency of heterozygous individuals (carrying one dominant and one recessive allele) is given by the term \$2pq$ in the Hardy-Weinberg equation.
Substitute the values of \(p\) and \(q\) into the heterozygous frequency formula: \(2 \times p \times q\).
Multiply the result by 100 to convert the frequency into a percentage, which represents the expected percentage of heterozygous individuals in the population.
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