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Multiple Choice
In a population where the frequency of the recessive allele (q) is 0.3, what percentage of individuals are expected to be heterozygous according to Hardy-Weinberg equilibrium?
A
21%
B
9%
C
49%
D
42%
Verified step by step guidance
1
Recall that according to the Hardy-Weinberg equilibrium, the allele frequencies are represented as $p$ for the dominant allele and $q$ for the recessive allele, where $p + q = 1$.
Given the frequency of the recessive allele $q = 0.3$, calculate the frequency of the dominant allele $p$ using the equation $p = 1 - q$.
The frequency of heterozygous individuals (carrying one dominant and one recessive allele) is given by the term $2pq$ in the Hardy-Weinberg equation.
Substitute the values of $p$ and $q$ into the heterozygous frequency formula: $2 \times p \times q$.
Multiply the result by 100 to convert the frequency into a percentage, which represents the expected percentage of heterozygous individuals in the population.