What is the name of the bacterial chromosomal region where replication begins?
Table of contents
- 1. Introduction to Genetics51m
- 2. Mendel's Laws of Inheritance3h 37m
- 3. Extensions to Mendelian Inheritance2h 41m
- 4. Genetic Mapping and Linkage2h 28m
- 5. Genetics of Bacteria and Viruses1h 21m
- 6. Chromosomal Variation1h 48m
- 7. DNA and Chromosome Structure56m
- 8. DNA Replication1h 10m
- 9. Mitosis and Meiosis1h 34m
- 10. Transcription1h 0m
- 11. Translation58m
- 12. Gene Regulation in Prokaryotes1h 19m
- 13. Gene Regulation in Eukaryotes44m
- 14. Genetic Control of Development44m
- 15. Genomes and Genomics1h 50m
- 16. Transposable Elements47m
- 17. Mutation, Repair, and Recombination1h 6m
- 18. Molecular Genetic Tools19m
- 19. Cancer Genetics29m
- 20. Quantitative Genetics1h 26m
- 21. Population Genetics50m
- 22. Evolutionary Genetics29m
7. DNA and Chromosome Structure
Bacterial and Viral Chromosome Structure
Problem 13
Textbook Question
Assume that a viral DNA molecule is a 50-µm-long circular strand with a uniform 20-Å diameter. If this molecule is contained in a viral head that is a 0.08-µm-diameter sphere, will the DNA molecule fit into the viral head, assuming complete flexibility of the molecule? Justify your answer mathematically.

1
Step 1: Calculate the volume of the viral DNA molecule. The DNA molecule is a cylindrical shape, so its volume can be calculated using the formula for the volume of a cylinder: \( V = \pi r^2 h \), where \( r \) is the radius and \( h \) is the length. Convert the diameter of the DNA (20 Å) to radius in micrometers (1 Å = 10^{-4} µm), and use the given length of 50 µm.
Step 2: Calculate the volume of the viral head. The viral head is a sphere, so its volume can be calculated using the formula for the volume of a sphere: \( V = \frac{4}{3} \pi r^3 \), where \( r \) is the radius of the sphere. Convert the diameter of the viral head (0.08 µm) to radius.
Step 3: Compare the volume of the DNA molecule to the volume of the viral head. If the volume of the DNA molecule is less than or equal to the volume of the viral head, the DNA molecule can fit inside the viral head. Otherwise, it cannot fit.
Step 4: Consider the assumption of complete flexibility. Since the problem states that the DNA molecule is completely flexible, it can be packed efficiently into the viral head, meaning the comparison of volumes is sufficient to determine if it fits.
Step 5: Conclude whether the DNA molecule fits into the viral head based on the mathematical comparison of the volumes calculated in steps 1 and 2.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Molecular Dimensions
Understanding the dimensions of both the viral DNA and the viral head is crucial. The DNA is a circular strand measuring 50 µm in length and 20 Å in diameter, while the viral head is a sphere with a diameter of 0.08 µm. Converting these measurements into consistent units is essential for accurate comparison.
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Geometric Volume and Surface Area
To determine if the DNA can fit inside the viral head, one must calculate the volume of the viral head and the effective volume occupied by the DNA. The volume of a sphere is calculated using the formula V = (4/3)πr³, while the DNA's configuration must be considered in terms of its length and diameter to assess how it can be accommodated.
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Flexibility of DNA
The assumption of complete flexibility of the DNA molecule is significant in this analysis. Flexible molecules can bend and coil, potentially allowing them to fit into smaller spaces than their linear dimensions suggest. This property must be factored into the mathematical justification of whether the DNA can fit within the confines of the viral head.
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