Mendel crossed peas having green seeds with peas having yellow seeds. The F₁ generation produced only yellow seeds. In the F₂, the progeny consisted of 6022 plants with yellow seeds and 2001 plants with green seeds. Of the F₂ yellow-seeded plants, 519 were self-fertilized with the following results: 166 bred true for yellow and 353 produced an F₃ ratio of 3/4 yellow: 1/4 green. Explain these results by diagramming the crosses.
Table of contents
- 1. Introduction to Genetics51m
- 2. Mendel's Laws of Inheritance3h 37m
- 3. Extensions to Mendelian Inheritance2h 41m
- 4. Genetic Mapping and Linkage2h 28m
- 5. Genetics of Bacteria and Viruses1h 21m
- 6. Chromosomal Variation1h 48m
- 7. DNA and Chromosome Structure56m
- 8. DNA Replication1h 10m
- 9. Mitosis and Meiosis1h 34m
- 10. Transcription1h 0m
- 11. Translation58m
- 12. Gene Regulation in Prokaryotes1h 19m
- 13. Gene Regulation in Eukaryotes44m
- 14. Genetic Control of Development44m
- 15. Genomes and Genomics1h 50m
- 16. Transposable Elements47m
- 17. Mutation, Repair, and Recombination1h 6m
- 18. Molecular Genetic Tools19m
- 19. Cancer Genetics29m
- 20. Quantitative Genetics1h 26m
- 21. Population Genetics50m
- 22. Evolutionary Genetics29m
2. Mendel's Laws of Inheritance
Pedigrees
Problem 15e
Textbook Question
The accompanying pedigree shows the transmission of albinism (absence of skin pigment) in a human family.

One child of female I-3 has albinism. What is the probability that any of the other four children are carriers of the allele for albinism?

1
Step 1: Understand the inheritance pattern of albinism. Albinism is typically inherited in an autosomal recessive manner, meaning that an individual must inherit two copies of the recessive allele (one from each parent) to express the trait. A carrier has one dominant allele and one recessive allele but does not express the trait.
Step 2: Analyze the pedigree. Female I-3 must be a carrier of the recessive allele for albinism because one of her children has albinism. This means that her genotype is heterozygous (Aa). The father of the children must also be heterozygous (Aa) or homozygous recessive (aa) for the child to inherit two recessive alleles.
Step 3: Determine the possible genotypes of the children. Using a Punnett square, cross the genotypes of the parents (Aa x Aa if both are heterozygous). The possible genotypes of the children are: AA (not a carrier), Aa (carrier), and aa (affected). The probabilities are 25% AA, 50% Aa, and 25% aa.
Step 4: Exclude the child with albinism from the calculation. Since one child is already known to have the genotype aa, focus on the remaining four children. For each of these children, the probability of being a carrier (Aa) is 50%, based on the Punnett square.
Step 5: Conclude that the probability of any of the other four children being carriers of the allele for albinism is 50%. This probability applies independently to each child, as genetic inheritance is random for each offspring.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Pedigree Analysis
Pedigree analysis is a diagrammatic method used to trace the inheritance patterns of traits through generations in a family. It helps identify whether a trait is dominant or recessive, and can indicate the likelihood of individuals being carriers of specific alleles. In this case, understanding the pedigree is crucial to determine the inheritance of albinism.
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Pedigree Flowchart
Autosomal Recessive Inheritance
Albinism is typically inherited in an autosomal recessive manner, meaning that an individual must inherit two copies of the recessive allele (one from each parent) to express the trait. Carriers possess one copy of the recessive allele and one dominant allele, which does not manifest the trait. Recognizing this pattern is essential for calculating the probability of the other children being carriers.
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Autosomal Pedigrees
Probability in Genetics
Probability in genetics involves calculating the likelihood of certain genotypes or phenotypes occurring in offspring based on parental genotypes. In this scenario, understanding the genetic makeup of the parents and the known child with albinism allows for the application of probability rules, such as the Punnett square, to estimate the chances that the other children are carriers of the albinism allele.
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Probability
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