Table of contents

1. Introduction to Genetics51m
2. Mendel's Laws of Inheritance3h 37m
3. Extensions to Mendelian Inheritance2h 41m
4. Genetic Mapping and Linkage2h 28m
5. Genetics of Bacteria and Viruses1h 21m
6. Chromosomal Variation1h 48m
7. DNA and Chromosome Structure56m
8. DNA Replication1h 10m
9. Mitosis and Meiosis1h 34m
10. Transcription1h 0m
11. Translation58m
12. Gene Regulation in Prokaryotes1h 19m
13. Gene Regulation in Eukaryotes44m
14. Genetic Control of Development44m
15. Genomes and Genomics1h 50m
16. Transposable Elements47m
17. Mutation, Repair, and Recombination1h 6m
18. Molecular Genetic Tools19m
- Genetic Cloning
  9m
- Methods for Analyzing DNA
  9m
19. Cancer Genetics29m
- Overview of Cancer
  21m
- Cancer Mutations
  7m
20. Quantitative Genetics1h 26m
21. Population Genetics50m
- Hardy Weinberg
  19m
- Allelic Frequency Changes
  31m
22. Evolutionary Genetics29m

8. DNA Replication

Overview of DNA Replication

Genetics

8. DNA Replication

Overview of DNA Replication

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1:19 minutes

Problem 19

Textbook Question

Suppose that E. coli synthesizes DNA at a rate of 100,000 nucleotides per minute and takes 40 minutes to replicate its chromosome.
(a) How many base pairs are present in the entire E. coli chromosome?
(b) What is the physical length of the chromosome in its helical configuration—that is, what is the circumference of the chromosome if it were opened into a circle?

Verified step by step guidance

Step 1: To determine the total number of base pairs in the E. coli chromosome, calculate the total number of nucleotides synthesized during replication. Multiply the synthesis rate (100,000 nucleotides per minute) by the replication time (40 minutes). This gives the total number of nucleotides synthesized during replication.

Step 2: Since DNA is double-stranded, the total number of nucleotides corresponds to the total number of base pairs. Therefore, the result from Step 1 directly represents the total number of base pairs in the E. coli chromosome.

Step 3: To calculate the physical length of the chromosome in its helical configuration, use the fact that the helical structure of DNA has approximately 10 base pairs per turn, and each turn of the helix spans 3.4 nanometers (nm). Multiply the total number of base pairs (from Step 2) by the length per base pair (0.34 nm, derived from 3.4 nm per 10 base pairs).

Step 4: To find the circumference of the chromosome if it were opened into a circle, note that the physical length calculated in Step 3 represents the total length of the chromosome. This length is equivalent to the circumference of the circular chromosome.

Step 5: Ensure all units are consistent throughout the calculations (e.g., converting nanometers to micrometers if needed) and verify the assumptions about DNA structure (e.g., 10 base pairs per turn and 3.4 nm per turn) are applied correctly.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

DNA Replication Rate

The DNA replication rate refers to the speed at which DNA polymerase synthesizes new DNA strands. In this case, E. coli synthesizes DNA at a rate of 100,000 nucleotides per minute. Understanding this rate is crucial for calculating the total number of nucleotides replicated over a given time period, which directly relates to the size of the chromosome.

Base Pairs in DNA

Base pairs are the building blocks of the DNA double helix, consisting of pairs of nucleotides (adenine-thymine and guanine-cytosine) that bond together. The total number of base pairs in a chromosome can be determined by multiplying the number of nucleotides by 2, as each nucleotide on one strand pairs with a complementary nucleotide on the opposite strand.

Physical Length of DNA

The physical length of DNA refers to the actual distance that the DNA molecule would occupy if it were stretched out. The circumference of a circular DNA molecule can be calculated using the number of base pairs and the average length of a base pair in its helical configuration, which is approximately 0.34 nanometers. This concept is essential for understanding the spatial organization of DNA within a cell.

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