Table of contents
- 1. Introduction to Genetics51m
- 2. Mendel's Laws of Inheritance3h 37m
- 3. Extensions to Mendelian Inheritance2h 41m
- 4. Genetic Mapping and Linkage2h 28m
- 5. Genetics of Bacteria and Viruses1h 21m
- 6. Chromosomal Variation1h 48m
- 7. DNA and Chromosome Structure56m
- 8. DNA Replication1h 10m
- 9. Mitosis and Meiosis1h 34m
- 10. Transcription1h 0m
- 11. Translation58m
- 12. Gene Regulation in Prokaryotes1h 19m
- 13. Gene Regulation in Eukaryotes44m
- 14. Genetic Control of Development44m
- 15. Genomes and Genomics1h 50m
- 16. Transposable Elements47m
- 17. Mutation, Repair, and Recombination1h 6m
- 18. Molecular Genetic Tools19m
- 19. Cancer Genetics29m
- 20. Quantitative Genetics1h 26m
- 21. Population Genetics50m
- 22. Evolutionary Genetics29m
2. Mendel's Laws of Inheritance
Inheritance in Diploids and Haploids
Problem B.1c
Textbook Question
Answer the following questions for autosomal conditions such as PKU.
If the first child of parents who are both heterozygous carriers of a recessive mutant allele is homozygous recessive, what is the chance the second child of the couple will be homozygous recessive? What is the chance the second child will be a heterozygous carrier of the recessive mutation?

1
Identify the genotype of the parents: Since both parents are heterozygous carriers of a recessive mutant allele, their genotypes can be represented as , where is the normal allele and is the recessive mutant allele.
Determine the possible genotypes of their children using a Punnett square: Cross (mother) with (father) to find the genotypic ratio of offspring. The possible genotypes are , , and .
Calculate the probability of the second child being homozygous recessive (): From the Punnett square, the chance of is 1 out of 4, or 25%. This probability is independent of the first child's genotype because each child's genotype is an independent event.
Calculate the probability of the second child being a heterozygous carrier (): From the Punnett square, the chance of is 2 out of 4, or 50%.
Summarize the results: The chance the second child is homozygous recessive is 25%, and the chance the second child is a heterozygous carrier is 50%, regardless of the first child's genotype.

This video solution was recommended by our tutors as helpful for the problem above
Video duration:
1mPlay a video:
Was this helpful?
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Autosomal Recessive Inheritance
Autosomal recessive inheritance occurs when a trait is expressed only if an individual inherits two copies of a mutant allele, one from each parent. Carriers have one normal and one mutant allele but typically do not show symptoms. For two heterozygous carriers, each child has a 25% chance of being affected, 50% chance of being a carrier, and 25% chance of being unaffected.
Recommended video:
Guided course
Autosomal Pedigrees
Independent Assortment and Probability in Genetics
Each child’s genotype is determined independently according to Mendelian genetics, meaning the outcome for one child does not affect the probabilities for the next. Thus, even if the first child is homozygous recessive, the chance for the second child to inherit the same genotype remains the same as the initial probability.
Recommended video:
Guided course
Gamete Genetics and Independent Assortment
Genotype Probabilities for Offspring of Carrier Parents
When both parents are heterozygous carriers, the possible genotypes for each child are: 25% homozygous recessive (affected), 50% heterozygous carrier (unaffected but carrier), and 25% homozygous dominant (unaffected, non-carrier). These probabilities apply independently to each child regardless of previous offspring’s genotype.
Recommended video:
Guided course
Probability
Related Videos
Related Practice
Multiple Choice
Which of the following correctly describes the genetic makeup of a haploid set and a diploid set in a eukaryotic cell?
1
views