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Multiple Choice
A comparison of the electron configurations of palladium (Pd) and silver (Ag) indicates that:
A
Ag has 2 more d electrons and the same number of s electrons as Pd.
B
Ag has 1 more d electron and the same number of s electrons as Pd.
C
Ag has 2 more d electrons and 1 less s electron than Pd.
D
Ag has 1 more d electron and 1 less s electron than Pd.
E
Ag has 1 more d electron and 1 more s electron than Pd.
Verified step by step guidance
1
Step 1: Begin by identifying the atomic numbers of palladium (Pd) and silver (Ag). Palladium has an atomic number of 46, and silver has an atomic number of 47.
Step 2: Write the electron configuration for palladium (Pd). The electron configuration is determined by filling the orbitals in order of increasing energy. For Pd, the electron configuration is [Kr] 4d^10 5s^0.
Step 3: Write the electron configuration for silver (Ag). Similarly, fill the orbitals for Ag, which has one more electron than Pd. The electron configuration for Ag is [Kr] 4d^10 5s^1.
Step 4: Compare the electron configurations of Pd and Ag. Notice that Ag has one more electron than Pd, which is added to the 5s orbital, resulting in Ag having 1 more s electron than Pd.
Step 5: Analyze the d electrons. Both Pd and Ag have the same number of d electrons, which is 10. Therefore, Ag does not have more d electrons than Pd.