Draw the condensed structural formula, or line-angle formula if cyclic, for each of the following: (12.1)
b. methyl propyl ether

Question

Draw the condensed structural formula, or line-angle formula if cyclic, for each of the following: (12.1)

b. methyl propyl ether

Accepted Answer

All right. Hi, everyone. So this question is asking us to sketch the condensed structural formula for Beto ethyl ether. And here we have four different answer choices labeled A through D. So lets go ahead and get started just for the record. Recall that a condensed structural formula is one that showcases all atoms in a molecule and how they are connected to each other. However, bonds to hydrogen are not necessarily shell instead, hydrogen atoms are grouped to the atoms that they are attached to as opposed to drawing lines in between them to showcase their bonds. So on that note, recall also that the ether functional group is one with a general formula of ror in which one oxygen atom is in between two alko groups. So here it just so happens that the name provided is the common name of a given ether in which the all kill groups are named in alphabetical order before the word ether. So here for the condensed structural formula, I'm first going to go ahead and draw oxygen and then I can focus my attention on the Ocu groups present specifically one beetle group and one EO group recall that a beetle group is four carbons, whereas an ethyl group is two carbons. And so for my condensed structural formula on one side of the oxygen, I'm going to draw a four carbon chain after I open up some more space for myself and on the other end of the chain or on the other end of the oxygen is a two carbon chain. So my last step here is to go ahead and showcase the hydrogens present in this compound. Recall that the carbon atoms of the ocho groups prefer to have ore bonds to stay neutral. So in my condensed structural formula, I have to group together all necessary hydrogens to make sure each carbon has four bonds. The outermost carbons, for example, because they only have one bond each require three hydrogens to make sure that they have four bonds. On the other hand, the internal carbons or the carbons inside of the structure here, they each have only two bonds to other atoms. So therefore, all of them are going to require two hydrogens to make sure that they all have four bonds. And so in my condensed structural formula, notice how I'm using 90 degree angles for all of my bonds and there you have it. So here we have an ether in with oxygen is in between a four carbon chain and a two carbon chain. And so this structure matches with option c in the multiple choice. And so with that being said, thank you so very much for watching. And I hope you found this helpful.

Draw the condensed structural formula, or line-angle formula if cyclic, for each of the following: (12.1)
b. methyl propyl ether

Verified video answer for a similar problem:

Key Concepts

Condensed Structural Formula

Line-Angle Formula

Ethers

Draw the condensed structural formula, or line-angle formula if cyclic, for each of the following: (12.1)b. methyl propyl ether

Verified video answer for a similar problem:

Key Concepts

Condensed Structural Formula

Line-Angle Formula

Ethers

Draw the condensed structural formula, or line-angle formula if cyclic, for each of the following: (12.1)
b. methyl propyl ether