Textbook Question
Complete the following equations. (Hint: Remember that a nitrogen with three groups bound to it has a lone pair and one with four does not)
a.
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17. Amines
Amine Reactions
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Determine the ammonium ion formed in the following reaction between diethylamine and hydrobromic acid.
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Verified step by step guidance1
Identify the reactants: Diethylamine (C2H5)2NH and hydrobromic acid (HBr).
Recognize that diethylamine is a secondary amine with a lone pair of electrons on the nitrogen atom, making it a base.
Understand that hydrobromic acid (HBr) is a strong acid that can donate a proton (H+).
In the reaction, the lone pair on the nitrogen atom of diethylamine will accept a proton from HBr, forming an ammonium ion.
The resulting ammonium ion will have the formula (C2H5)2NH2+, where the nitrogen atom now has four bonds and a positive charge.
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