Table of contents

1. Matter and Measurements4h 31m
2. Atoms and the Periodic Table5h 23m
3. Ionic Compounds2h 18m
4. Molecular Compounds2h 18m
5. Classification & Balancing of Chemical Reactions3h 17m
6. Chemical Reactions & Quantities2h 27m
7. Energy, Rate and Equilibrium3h 46m
8. Gases, Liquids and Solids3h 25m
9. Solutions4h 10m
10. Acids and Bases3h 29m
11. Nuclear Chemistry56m
BONUS: Lab Techniques and Procedures1h 38m
BONUS: Mathematical Operations and Functions47m
12. Introduction to Organic Chemistry1h 34m
13. Alkenes, Alkynes, and Aromatic Compounds2h 12m
14. Compounds with Oxygen or Sulfur1h 6m
15. Aldehydes and Ketones1h 1m
16. Carboxylic Acids and Their Derivatives1h 11m
17. Amines39m
18. Amino Acids and Proteins1h 51m
19. Enzymes1h 37m
20. Carbohydrates1h 41m
21. The Generation of Biochemical Energy2h 8m
22. Carbohydrate Metabolism2h 22m
23. Lipids2h 26m
24. Lipid Metabolism1h 45m
25. Protein and Amino Acid Metabolism1h 37m
26. Nucleic Acids and Protein Synthesis2h 54m

13. Alkenes, Alkynes, and Aromatic Compounds

Naming Alkenes

GOB Chemistry

13. Alkenes, Alkynes, and Aromatic Compounds

Naming Alkenes

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Problem 32b

Textbook Question

Draw the condensed structural formula for each of the following:
b. trans-2-pentene

Verified step by step guidance

Step 1: Understand the structure of trans-2-pentene. 'Pentene' indicates a five-carbon alkene, and '2' specifies that the double bond is located between the second and third carbons in the chain. 'Trans' means the substituents on either side of the double bond are on opposite sides.

Step 2: Begin by drawing the backbone of the molecule, which consists of five carbon atoms connected in a straight chain. Label the carbons as C1, C2, C3, C4, and C5.

Step 3: Place the double bond between C2 and C3. Ensure that the double bond is clearly indicated in the structure.

Step 4: Add hydrogen atoms to each carbon to satisfy the valency of carbon (four bonds per carbon atom). For the trans configuration, place the hydrogen atoms on C2 and C3 on opposite sides of the double bond.

Step 5: Write the condensed structural formula by grouping the atoms bonded to each carbon. For example, C1 will have three hydrogens (CH3), C2 will have one hydrogen and a double bond to C3 (CH), and so on. Ensure the trans configuration is reflected in the formula.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Condensed Structural Formula

A condensed structural formula is a way of representing a chemical compound that shows the arrangement of atoms and the connectivity between them without depicting all the bonds explicitly. It simplifies the structure by grouping atoms together, often indicating the number of hydrogen atoms attached to each carbon atom. This format is particularly useful for organic compounds, allowing for a clearer understanding of their structure and composition.

Trans Isomerism

Trans isomerism is a type of geometric isomerism where substituents are positioned on opposite sides of a double bond or a ring structure. In the case of alkenes like trans-2-pentene, this configuration affects the physical and chemical properties of the compound, such as boiling point and reactivity. Understanding trans isomerism is crucial for accurately drawing and interpreting the structure of compounds with double bonds.

Pentene Structure

Pentene refers to a class of alkenes with five carbon atoms and at least one double bond. The '2' in trans-2-pentene indicates that the double bond is located between the second and third carbon atoms in the chain. Recognizing the basic structure of pentene is essential for constructing its condensed structural formula, as it provides the framework for identifying how the atoms are arranged and how they interact with one another.

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