Complete and balance the equation for each of the following reactions:
a. ZnCO₃(s) + HBr(aq) →

Question

Complete and balance the equation for each of the following reactions:

a. ZnCO₃(s) + HBr(aq) →

Accepted Answer

Welcome back, everyone. We need to provide the products for the reaction of hydro Bromma acid with Cobalt two carbonate and balance the chemical equation. We're given half of our reaction between Cobalt two carbonate and hydro brom acid. We're going to begin by categorizing our two reagents. Looking at Cobalt two carbonate, we're going to recognize that Cobalt based on its position in our transition metal D block is considered a metal. And we have the combination of a metal bonded to our poly atomic ion, which is our carbonate C 032 minus an ion which is a poly atomic ion. So because we have a metal bonded to a poly atomic ion, therefore, our first reactant is ionic and looking at our second reactant, we have H B R in which we have our proton H plus bonded to our bromide one minus anion. So we have two nonmetals, hydrogen and bromine bonded to one another. And therefore this is a covalent or molecular compound. Recall that H B R is representative as one of our memorized strong acids from our textbooks. Now, what we can summarize is that we have a metal carbonate reacting with an acid recall that when we have a metal carbonate reacting with an acid, our products would be carbon dioxide gas, liquid water as well as a salt in which to get the formula of our salt, we would take our metal from our ionic compound reactant bonded to our anion from our acid reactant. So writing out our equation, we would have Cobalt two carbonate C O C 03 which is a insoluble carbonate. So it gets a solid symbol reacting with hydroponic acid which is aqueous. And on our product side, we form carbon dioxide gas as well as liquid water. And then for our salt, we have our metal Cobalt which is bonded to our anion from hydroponic acid being bromine. Now recall that Cobalt is a transition metal and would form a two plus ion. So we would give a subscript of two next to bromine in our chemical formula for Cobalt two bromine or for Cobalt two bromide. We're going to want to next recall our solubility rules for bromides. And based on it being bonded to Cobalt here, this is a soluble bromide. So we give it the label A Q because it's aqueous and soluble in water. So now with our reaction written out, we need to ensure that it is a balanced reaction by comparing our atoms on the reactant side. Cobalt carbon, hydrogen oxygen. And then we have bromine to the same atoms on the product side. Cobalt carbon, hydrogen oxygen. And bromine. On our reactant side, we count one Cobalt, a total of one carbon given by the subscript of three in Cobalt, two carbonate. We have three oxygens, we have one hydrogen and then we have one bromine. Next. For our product side, we can count a total of one atom of Cobalt. For carbon. We can count a total of one atom for hydrogen given by the subscript of two in our product water, we can count a total of two hydrogens. For oxygen given by the subscript of two in carbon dioxide. We have two oxygens plus the one oxygen. In our second product water would give us a total of three oxygens on the product side. And then for bromine given by the subscript of two in Cobalt two bromide, we have a total of two bromine. So we're going to begin by focusing on balancing out our non hydrogen and non oxygen atoms first, which in this case would be our imbalanced bromine. We have two moles of bromine on the product side. So to compensate for that on the reactant side, since we only have one, we're going to place a coefficient of two in front of our reactant hydroponic acid, which will now change our hydrogens on the reactant side to a total of two and will change our bromine on the reactant side to a total of two. Now, with this coefficient added, we can confirm that we have a balanced equation since we have the same number of each type of atom on both sides of our equation. And so our final answer is going to be that one mole of Cobalt two carbonate reacts with two moles of hydroponic acid to form one mole of carbon dioxide gas, one mole of water and one mole of Cobalt two bromide. And this entire balanced equation is going to be our final answer. I hope that this made sense and let us know if you have any questions.

Complete and balance the equation for each of the following reactions:
a. ZnCO₃(s) + HBr(aq) →

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Complete and balance the equation for each of the following reactions:
a. ZnCO₃(s) + HBr(aq) →