Draw the condensed structural formula for the alcohol formed when each of the following is reduced by hydrogen in the presence of a nickel catalyst:
d. 2-methyl-3-pentanone

Question

Draw the condensed structural formula for the alcohol formed when each of the following is reduced by hydrogen in the presence of a nickel catalyst:

d. 2-methyl-3-pentanone

Accepted Answer

Welcome back, everyone. Our next problem says, provide the alcohol product of the following reaction using a condensed structural formula, the production of three methyl four hepton know by hydrogen in the presence of a palladium catalyst. So looking at our original molecule set ending on, tells us we have a ketone and reduction of a ketone by hydrogen will yield a secondary alcohol. And we just need to find this structure. So we call that, that general formula. Our kone will be R and then C double Bondo with an R prime. And when we reduce it, we add hydrogens ready to go plus H two palladium catalyst. So PD over our arrow and we get our RC now instead of a double bond to the oxygen, it has a single bond to an oh group and the carbon gets a hydrogen as well, which it can now take since its double bond is broken and then our prime. So let's think about that in light of our reacting substance. So we have a Hep Denno. So it would be a seven carbon chain. I'm going to draw that as a skeletal structure just because it's a little easier to keep track, we'll convert back to a condensed structural formula to get our answer. So I've got a seven carbon chain, 1234567, always double check your carbons on a long chain like this. In case you've gotten mixed up 1234567, the ketone, our number tells us it's four HEP known will be in carbon four. So 1234 right smack out in the middle that carbon is bonded to or double bonded to an oxygen. So when we add hydrogen in the presence of palladium catalyst, we're going to add an a hydrogen and break that double bond. So we'll still have a seven carbon chain. Oop I forgot when looking at my name, it said three methyl four hepton know. So we didn't add the methyl group that goes on carbon three adjacent to the keto. So let's look at our product. We have our seven carbon chains still 1234567 67, double check that the ketone that was on carbon four is now an oh group with another hydrogen added to that carbon. So originally had no hydrants. Now it has one. So now we know that we have this alcohol here. Let's add our methyl group to the adjacent carbon and we need to draw a condensed structural formula for the answer. So we have seven carbons. So we had the first one ch three, the second one CH two, it has no substituents. Carbon three has a methyl group. So we have ch and then our methyl group C three attached to it. So now we're on carbon three. Now we're to carbon four. This had the ketone and now has an alcohol. So we have C and then a lineup going to, oh and then finally we've got 123 more carbons. So ch two ch two ch three. So we've got 1234567 carbons with a methyl group on carbon three and an alcohol group on carbon four. That's the result of reducing a ketone group that was there. So we have our condensed structural formula for that problem. See you in the next video.

Draw the condensed structural formula for the alcohol formed when each of the following is reduced by hydrogen in the presence of a nickel catalyst:
d. 2-methyl-3-pentanone

Verified video answer for a similar problem:

Key Concepts

Reduction Reaction

Condensed Structural Formula

Nickel Catalyst

Draw the condensed structural formula for the alcohol formed when each of the following is reduced by hydrogen in the presence of a nickel catalyst:d. 2-methyl-3-pentanone

Verified video answer for a similar problem:

Key Concepts

Reduction Reaction

Condensed Structural Formula

Nickel Catalyst

Draw the condensed structural formula for the alcohol formed when each of the following is reduced by hydrogen in the presence of a nickel catalyst:
d. 2-methyl-3-pentanone