Draw the condensed structural formulas and write the IUPAC names for two structural isomers of the carboxylic acids that have the molecular formula C₄H₈O₂.

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Welcome back, everyone propose plausible structures and systematic names of the carboxylic acid isomers of the compound with the molecular formula C five H 1002. First of all, we have a form of CNH two N because there's 10 hydrogen atoms or five carbon atoms. So twice as large of a number, right, followed by 02. And this is a general form of a carboxylic acid which doesn't have any additional pi bonds. So we are ready to begin drawing the structures. And what we want to do is first of all, begin with a five member chain. Let's draw the functional group of a carboxylic acid which is coo H and then we want a total of five carbon atoms. So we have one within car bono, followed by the second one, the third one, the fourth one and then the fifth one. So we have a five member chain. And our goal or basically our strategy is to keep shortening it and adding branching to our. So we have the first one and now we are going to show them the five member chain into a four member chain. Now, how do we do that? Well, we are going to eliminate the muscle group at the end. And instead we're going to add it to carbon number 123. Right. Essentially, to get the simplest possible branching from here. Instead of adding it to carbon number three, we can also add it to carbon number two. So now instead of carbon number three, we're adding it to carbon number two, this gives us an additional structure. We cannot shift that to the right anymore, right? Because essentially we want to read in her box, but we can shorten our parent into a three member chain. That's the shortest we can get. So let's draw a three member chain, 12 and three. And what we can do from here is simply add the remaining carbons bonded to position number two. So we need two more carbon atoms and we got a quaternary carbon. This is a different structure. Now, we cannot shorten our parent anymore. So we can just name those structures. Let's begin with the first one and the first one is a 12345 member chain which is Panino acid. Fanta means five, right? We always use a suffix of O I followed by acid. Now, what about structure number two? Now, in this case, that would be Beatson OIC acid because the longest continuous carbon chain has 1234 carbons. So it's Beatson OIC acid and we want to add the methyl substitute, which is bonded to carbon number three. So instead of being Beano acid, it is actually we methyl Beano acid in this case, because the parent is branched. What about structure? Number three? Well, it's another besic acid because we have 1234 carbons. So we can say beats in our cassette and then we have the methyl substi bonded to carbon number two. So it's two methyl. The reason why it's carbon number two is once again because carbonyl defines carbon number one and we start counting from right to left. So if we combine two metal with beat soo a asset, we're going to get the final name. It's, it's two methyl Beano acid. And what about the final one? Well, it is a three member chain. So we have prono acid and there are two methyl substituents bonded to position number two. So that'd be two comma two. We have to use a prefixed dye which means two, two methyl substituents. So T comma two dimethyl means that position number two and position number two. Again, those have two methyl substituents and simply speaking, position number two is equivalent to itself. So it means that there are two metal substitutions bonded to the same carbon number two. And we have got the structures as well as the names. Thank you for watching.

Draw the condensed structural formulas and write the IUPAC names for two structural isomers of the carboxylic acids that have the molecular formula C₄H₈O₂.

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Verified video answer for a similar problem:

Key Concepts

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Draw the condensed structural formulas and write the IUPAC names for two structural isomers of the carboxylic acids that have the molecular formula C₄H₈O₂.