Join thousands of students who trust us to help them ace their exams!
Multiple Choice
At a temperature of and a pressure of , which element would most likely be in the liquid phase?
A
Bromine ()
B
Cesium ()
C
Mercury ()
D
Chlorine ()
0 Comments
Verified step by step guidance
1
Step 1: Understand the problem context. We are asked to determine which element is most likely to be in the liquid phase at 1000.0 K and 1 atm pressure. This requires knowledge of the elements' boiling points relative to the given temperature.
Step 2: Recall or look up the boiling points of the given elements (Bromine, Cesium, Mercury, Chlorine) in Kelvin. The boiling point is the temperature at which a substance changes from liquid to gas at 1 atm pressure.
Step 3: Compare the boiling points of each element to the given temperature (1000.0 K). If the boiling point is higher than 1000.0 K, the element will remain liquid at that temperature and pressure. If it is lower, the element will be in the gas phase.
Step 4: Identify which element has a boiling point just above 1000.0 K, indicating it would be liquid at 1000.0 K and 1 atm. Elements with boiling points below 1000.0 K will be gases, and those with much higher boiling points might still be solid or liquid depending on melting points.
Step 5: Conclude that the element with a boiling point above 1000.0 K and below its melting point at this temperature would be liquid. This reasoning leads to the correct choice without directly calculating the phase.