Use the following table for problems 9.25 to 9.28:
A solution containing 80. g of KCl in 200. g of H₂O at 50 °C is cooled to 20 °C.a. How many grams of KCl remain in solution at 20 °C?
Verified step by step guidance
1
Identify the solubility of KCl at 50 °C and 20 °C using the provided table.
Determine how much KCl can dissolve in 200 g of H₂O at 20 °C based on the solubility data.
Calculate the difference between the initial amount of KCl (80 g) and the amount that can remain dissolved at 20 °C.
The difference will indicate how much KCl will precipitate out of the solution as it cools from 50 °C to 20 °C.
Subtract the precipitated amount from the initial 80 g to find the grams of KCl remaining in solution at 20 °C.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Solubility
Solubility refers to the maximum amount of a solute that can dissolve in a solvent at a given temperature and pressure. For KCl in water, solubility changes with temperature; typically, as temperature decreases, solubility also decreases, leading to potential precipitation of the solute. Understanding the solubility curve for KCl is essential to determine how much remains dissolved when the solution is cooled.
The saturation point is the stage at which a solution can no longer dissolve additional solute at a specific temperature. When a solution is saturated, any excess solute will precipitate out. In this problem, knowing the saturation point of KCl at 20 °C is crucial to determine how much KCl remains in solution after cooling.
Temperature significantly affects the solubility of most solids in liquids. Generally, higher temperatures increase solubility, allowing more solute to dissolve. Conversely, cooling a solution can lead to decreased solubility, which may result in some solute crystallizing out of the solution. This concept is vital for predicting the behavior of KCl when the solution is cooled from 50 °C to 20 °C.