Do the following reactions favor reactants or products at equilib...

Question

Do the following reactions favor reactants or products at equilibrium? Give relative concentrations at equilibrium.Sucrose(aq) + H2O(l) ⇌ Glucose(aq) + Fructose(aq) K = 1.4 x 10^5

Accepted Answer

Welcome back, everyone. We need to consider the equilibrium process where our equilibrium constant K is equal to 34 at 25 Celsius, we have Aquarius lactose reacting with one mole of liquid water in equilibrium with one mole of glucose and one mole of acquis galactose is the formation of the products favored at equilibrium. And what are the relative concentrations of the species involved at equilibrium? Let's begin by recalling that since our equilibrium constant equal to 34 is positive, this means that therefore our formation of products and sorry, this should say formation of products is going to be favored at equilibrium. So whenever we have a positive equilibrium constant value K R formation of products is favored. Let's recall that our equilibrium constant K describes our concentration of products divided by our concentration of reactant. In terms of our given reaction, we would have our concentration of only our acquis products being our concentration of glucose times our concentration of galactose divided by our concentration of our only Aquarius reactant where we just have our concentration of lactose in our denominator. And again, this is Aquarius re agents only since liquid should not be included. So now for the relative concentrations of each species involved, beginning with our concentration of glucose, We would find this by plugging in our equilibrium constant. Given as K- 34, we're setting this equal to our concentration of glucose and the numerator multiplied by a concentration of galactose in our numerator as well divided by our concentration of lactose are only Aquarius reacting in the denominator. So to isolate for our concentration of glucose, we're going to multiply both sides of our equation by the inverse where we have our concentration of lactose divided by our concentration of galactose. So that will cancel out those terms on the right hand side. And we're going to multiply by that same inverse fraction on the reactant side. So that we can find that our concentration of glucose Is going to equal 34 times our concentration of lactose divided by our concentration of galactose. And this would be our first answer as our relative concentration of glucose Or how to calculate it at least. And we can also confirm our answer that because our equilibrium constant is equal to 34, which is positive, our formation of products is favored at equilibrium. So next, let's find our concentration of galactose at equilibrium. So plugging in our equation and I'll just copy and paste it from before. So we now want to isolate our equation for our concentration of galactose. And so we're also just going to multiply by the inverse where we have on our right hand side, we're multiplying by concentration of lactose divided by our concentration of glucose on both sides. So that it will cancel out those two terms. On the right. And on the left, we multiply by sorry, our concentration of lactose divided by our concentration of glucose. So an inverse fraction and what we would find is that our concentration of galactose at equilibrium Is equal to times our concentration of lactose divided by our concentration of glucose. And this would be our next relative concentration of one of our re agents being galactose. In this case, next, we just need our concentration of lactose at equilibrium. So to show the work for that, we use our same equilibrium setup where our first step is going to be multiplying by our concentration of lactose on both sides of our equation so that it cancels out on the right. And in our next line, we have 34 and let's use blue, we have 34 times our concentration of lactose equal to our concentration of glucose times our concentration of galactose. And to completely isolate for our concentration of lactose will divide by the reciprocal of 1/34 on both sides of our equation. So it will cancel out our 34 on the right, on the left hand side. Sorry. And we'll find that our concentration of lactose is equal to 1/34 multiplied by our concentration of glucose times our concentration of galactose. And this is going to be our final answer for our relative concentration of lactose in this case. So all of our answers that we've outlined highlighted in yellow will correspond to choice c in the multiple choice as our final answer. I hope this made sense and let us know if you have any questions.

Do the following reactions favor reactants or products at equilibrium? Give relative concentrations at equilibrium.Sucrose(aq) + H2O(l) ⇌ Glucose(aq) + Fructose(aq) K = 1.4 x 10^5

Key Concepts

Chemical Equilibrium

Equilibrium Constant (K)

Relative Concentrations

Watch next