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Multiple Choice
In the following carbon skeleton structure, which carbon atom(s) exhibit hybridization? (Assume the structure is =--)
A
Carbons 1 and 2
B
Carbons 3 and 4
C
Carbons 2 and 3
D
Only carbon 2
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Verified step by step guidance
1
Identify the carbon atoms in the given structure: CH\_2=CH\_1-CH\_2-CH\_3, where the subscripts indicate the carbon numbering.
Recall that sp\^2 hybridization occurs in carbon atoms that form a double bond, involving one sigma bond and one pi bond.
Examine the double bond between carbon 1 (CH\_1) and carbon 2 (CH\_2). Both carbons involved in this double bond will be sp\^2 hybridized.
Check the other carbons (carbon 3 and carbon 4) which are single bonded only; these carbons are typically sp\^3 hybridized because they form four sigma bonds.
Conclude that the carbon atoms exhibiting sp\^2 hybridization are carbons 1 and 2, as they are directly involved in the double bond.