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Multiple Choice
Which of the following reaction conditions results in Markovnikov addition to an unsymmetric alkene?
A
Addition of in the presence of peroxides
B
Addition of in the presence of and (oxymercuration-demercuration)
C
Addition of in the presence of followed by (hydroboration-oxidation)
D
Addition of in the presence of dilute
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1
Understand that Markovnikov addition refers to the regioselectivity where the proton (H\+) adds to the carbon of the double bond with more hydrogens, and the other part (e.g., OH) adds to the more substituted carbon.
Analyze the reaction conditions given: Addition of H2O in the presence of peroxides typically leads to anti-Markovnikov addition due to a radical mechanism.
Oxymercuration-demercuration (Hg2+ and OAc2) is known to give Markovnikov addition without carbocation rearrangement, so this is a strong candidate.
Hydroboration-oxidation (B2H6 followed by H2O2) results in anti-Markovnikov addition because the boron adds to the less substituted carbon.
Addition of H2O in the presence of dilute H2SO4 proceeds via a carbocation intermediate, which leads to Markovnikov addition due to the stability of the carbocation formed on the more substituted carbon.