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Multiple Choice
Based on the curved arrow formalism given, predict the products of this acid/base reaction.
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B
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1
Identify the reactants: The first image shows an amine (ethylamine) and an alcohol (ethanol) with curved arrows indicating electron movement.
Analyze the curved arrows: The arrow from the nitrogen atom of the amine to the hydrogen atom of the alcohol indicates that the nitrogen is donating a pair of electrons to form a bond with the hydrogen.
Consider the acid-base reaction: The amine acts as a base, accepting a proton (H+) from the alcohol, which acts as an acid.
Predict the products: The proton transfer results in the formation of an ammonium ion (protonated amine) and an alkoxide ion (deprotonated alcohol).
Draw the products: The ammonium ion will have a positive charge on the nitrogen, and the alkoxide ion will have a negative charge on the oxygen, as shown in the second image.