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Multiple Choice
Predict the molecule in each series with the higher boiling point.
A
I, III
B
I, IV
C
II, III
D
II, IV
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1
Identify the functional groups present in each molecule. In Series A, molecule I has an alcohol group (-OH) and molecule II has an amine group (-NH2). In Series B, molecule III has a primary amine group (-NH2) and molecule IV has a tertiary amine group (N(CH3)2).
Understand the impact of hydrogen bonding on boiling points. Alcohols can form stronger hydrogen bonds compared to amines due to the higher electronegativity of oxygen compared to nitrogen. This generally results in higher boiling points for alcohols.
Compare the boiling points of molecules in Series A. Molecule I, with an alcohol group, is expected to have a higher boiling point than molecule II, which has an amine group, due to stronger hydrogen bonding in alcohols.
Compare the boiling points of molecules in Series B. Molecule III, with a primary amine group, can form hydrogen bonds, whereas molecule IV, a tertiary amine, cannot form hydrogen bonds as effectively due to the lack of hydrogen atoms bonded to the nitrogen. Therefore, molecule III is expected to have a higher boiling point than molecule IV.
Conclude that the molecules with the higher boiling points in each series are I in Series A and III in Series B, leading to the correct answer: I, III.