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Multiple Choice
In the electrophilic addition of to propene, what is the major organic product formed?
A
(propanal)
B
(2-propanol)
C
(1-propanol)
D
(propanoic acid)
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Verified step by step guidance
1
Identify the reactants and the type of reaction: propene (an alkene) undergoes electrophilic addition with water (H\_2O) in the presence of an acid catalyst, typically H\+, which adds across the double bond.
Recall the mechanism of electrophilic addition of water to an alkene: the alkene's double bond acts as a nucleophile and attacks a proton (H\+), forming a more stable carbocation intermediate.
Determine the carbocation intermediate formed: apply Markovnikov's rule, which states that the proton (H\+) adds to the carbon with more hydrogens, leading to the more stable carbocation on the more substituted carbon.
Next, the water molecule (H\_2O) acts as a nucleophile and attacks the carbocation, forming an oxonium ion intermediate, which then loses a proton to give the alcohol product.
Conclude the major organic product: since the carbocation forms on the secondary carbon, the OH group attaches there, resulting in 2-propanol as the major product.