Draw the condensed structure for each of the following:

Question

d. vinyl bromide

e. 1,2-dimethylcyclopentene

f. diallylamine

Accepted Answer

Hey everyone and welcome back in today's video. We are going to write the appropriate condensed structures for the compounds. Kevin below number one, vinyl chloride. Number 213 D metal cycle hack scene. Number three alot vinyl, I mean, starting with number one, we want to draw a condensed structure for vinyl chloride. Now to begin with, we just want to remember what a vinyl group is and you may recall the simplest alc in which is the theme That would be two carbon atoms bonded via a double bond And each carbon has two hydrogen atoms. If we remove one of the two hydrogen atoms bonded to any of the two carbons, let's suppose the second carbon, we will have see each instead of siege two and that will be our final substitution in general. So this is our final group because the problem suggests that we have vinyl chloride. We are just going to add chlorine to our vinyl substation just over here where we are creating our carbon bond to a specific group. And what we are getting here is the following. We have H two C. We have to expand that double bond because it corresponds to our elk in Park, right? Whenever we have some multiplicity of bonds instead of just single bonds, we are going to clearly show that this is either a double bond or a triple bonds, we have to expand that double bond. Then we are drawing our next carbon which has carbon bonded to hydrogen and then bonded to chlorine, right? Because we're creating that carbon chlorine bonds. So that's vinyl chloride. Let's label this is our final answer for the first one and we are ready to move on to the second one, 13 D metal cycle vaccine. If we start with our parents, it's psycho vaccine. And you may remember that psycho vaccine corresponds to a ring which has six carbon atoms because we have hacks. So we are going to draw a six member ring first of all. So let's bond six carbon atoms in a cyclic structure. That's 1, 2, 3, 4, 56 because it's psycho hack seen the suffix scene corresponds to the fact that this is an elk in. So we may add a double bond between any two carbon atoms. So we have added a double bond and we understand that positions one and three have two metal substitutions because we have die metal, which means to metal groups, one comma three means that there are two metal groups at carbons. One and three. Recall that the first carbon is defined by the position of the double bond. So this is our first carbon atom. This is our second one and the third one based on the structure. So we went to add two metal groups as Carbons one and 3. So let's draw them At the first carbon atom. We have our CE three group. Now going clockwise because our double bond always starts at carbon. Number one, we add C three at position three. And we have shown all of our bonds for the ring. Because whenever you want to do a condensed structure, you definitely want to show these carbon carbon bonds within a ring. Otherwise, it's not really possible to clearly depict a ring, right? So not only we are showing our double bond, we're also showing our single bonds within the ring and also the substitutions bonded to each carbon within the ring. We're expanding these carbon carbon bonds. Okay, well done. So the word last thing we want to do here is just add the remaining hydrogen atoms going clockwise. The first carbon atom doesn't need any high genes. It has four bonds. The next one needs one hygiene because it has three bonds, one more hygiene to the next carbon because it has three bonds. The next one will have to hide jeans because it has two bonds to Hye Jin's to Hye Jin's because the other carbons also have two bonds only. So this is our condensed structure. Let's label this is our final answer. four, the metal cycle vaccine. And now finishing with number three, we have a little vinyl. I mean, we already know what a vinyl group is, is basically ceased to bonded to ch and then we are essentially bonding this group to something that we're given right now, then we're analyzing alot. So this is our vinyl. And now for a, well, you just want to remember how propane looks like propane is the second simplest al keen which has carbon carbon double bond. We want to add two hydrogen atoms to have four bonds here at the first carbon atom. For the second one, it will be bonded to the third carbon because we have a protein chain. So that means the middle carbon needs one hydrogen. So we're going to add ch and the third carbon atom only has one bond. So it needs three hydrogen atoms. So to turn it into an aloe group, we are just going to remove one hydrogen from the C three group and we are going to turn it into a C three group. And therefore we can now bond this carbon to something else that were given in our name. And this something is, I mean recall that amines are basically ammonia structures in which you're replacing 12 or three hydrogen atoms and essentially replacing those Hae Jin's with l kill groups because the name suggests that we have a little vinyl, that means we are going to replace two hydrogen atoms with these groups. So if you do that, you will clearly see the following. If we not worry about the condensed structure yet, you're just going to replace one or two of the three high jeans with vinyl and a little groups. So we're going to bond this carbon within vinyl group to an Irish in. So you, you will get the following. You have ch bonded to or basically let's change the angle. We can just say CH as bonded to cease to. And then for the next one, we have a little group. So that would be sieged too bonded to Ch which in turn is bonded to Ch two. That's our structure. We just want to turn it into its condensed form to draw its condensed form. We can just use that hydrogen and add it to nitrogen immediately because it's bonded to nitrogen and we can just go from right or basically from bottom to top and then downwards to clearly see how our longest chain would look like. So if we draw out all of our atoms, we would start with seeds too, then we would have double bond CH. Now this ch is bonded to cease to be a single bond, but we don't want to show that single bond, right? Because we're only expanding double bonds here. So that B CH C S two than in our structure, we have an age which is bonded to CH. So we're going to say NH CH and that carbon is bonded to cease to be a double bonds. We have to clearly show that double bond and that will be our final structure. Now, looking at the three structures, we may conclude that the correct answer to the multiple choice question is a, thank you for watching and I will see you in the next video.

Draw the condensed structure for each of the following:
d. vinyl bromide
e. 1,2-dimethylcyclopentene
f. diallylamine

Key Concepts

Condensed Structural Formula

Cycloalkenes

Amines

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