In a certain region of space near Earth’s surface, a uniform horizontal magnetic field of magnitude B exists above a level defined to be y = 0. Below y = 0, the field abruptly becomes zero (Fig. 29–63). A vertical square wire loop has resistivity ρ, mass density ρm, diameter d, and side length ℓ. It is initially at rest with its lower horizontal side at y = 0 and is then allowed to fall under gravity, with its plane perpendicular to the direction of the magnetic field. (a) While the loop is still partially immersed in the magnetic field (as it falls into the zero-field region), determine the magnetic “drag” force that acts on it at the moment when its speed is υ. (b) Assume that the loop achieves a constant terminal velocity VT before its upper horizontal side exits the field. Determine a formula for VT. (c) If the loop is made of copper and B = 0.80 T, find VT.
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30. Induction and Inductance
Motional EMF
Problem 55c
Textbook Question
INT A 20-cm-long, zero-resistance slide wire moves outward, on zero-resistance rails, at a steady speed of 10 m/s in a 0.10 T magnetic field. (See Figure 30.26.) On the opposite side, a 1.0 Ω carbon resistor completes the circuit by connecting the two rails. The mass of the resistor is 50 mg. If the wire is pulled for 10 s, what is the temperature increase of the carbon? The specific heat of carbon is 710 J/kg K.

1
Step 1: Calculate the electromotive force (EMF) induced in the slide wire using Faraday's law of induction. The formula for EMF is \( \text{EMF} = B \cdot v \cdot L \), where \( B \) is the magnetic field strength (0.10 T), \( v \) is the velocity of the wire (10 m/s), and \( L \) is the length of the wire (0.20 m).
Step 2: Determine the current \( I \) flowing through the circuit using Ohm's law. The formula is \( I = \frac{\text{EMF}}{R} \), where \( R \) is the resistance of the carbon resistor (1.0 Ω).
Step 3: Calculate the power dissipated in the resistor using the formula \( P = I^2 \cdot R \). This represents the rate at which electrical energy is converted into heat in the resistor.
Step 4: Find the total energy dissipated over the 10-second interval. Use the formula \( E = P \cdot t \), where \( t \) is the time duration (10 s). This gives the total heat energy transferred to the resistor.
Step 5: Calculate the temperature increase of the carbon resistor using the formula \( \Delta T = \frac{E}{m \cdot c} \), where \( m \) is the mass of the resistor (50 mg or 0.00005 kg) and \( c \) is the specific heat capacity of carbon (710 J/kg K).

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Electromagnetic Induction
Electromagnetic induction is the process by which a changing magnetic field within a closed loop induces an electromotive force (EMF) in the wire. In this scenario, as the slide wire moves through the magnetic field, it experiences a change in magnetic flux, leading to the generation of an induced current that flows through the circuit, including the resistor.
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Joule Heating
Joule heating, also known as resistive heating, occurs when an electric current passes through a resistor, converting electrical energy into thermal energy. The amount of heat generated can be calculated using the formula Q = I²Rt, where Q is the heat produced, I is the current, R is the resistance, and t is the time. This principle is crucial for determining the temperature increase of the carbon resistor.
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Specific Heat Capacity
Specific heat capacity is the amount of heat required to raise the temperature of a unit mass of a substance by one degree Celsius (or one Kelvin). It is a material-specific property, and for carbon, it is given as 710 J/kg K. This concept is essential for calculating the temperature change of the carbon resistor after it absorbs the heat generated from the current flowing through it.
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