Suppose it takes 75 kW of power for your car to travel at a constant speed on the highway. If this capacitor were to be made from activated carbon (Section 24–2), the voltage would be limited to no more than 10 V. In this case, how many grams of activated carbon would be required?
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Capacitors & Capacitance
Problem 14
Textbook Question
(II) Use Gauss’s law to show that inside the inner conductor of a cylindrical capacitor (see Fig. 24–7 and Example 24–2) as well as outside the outer cylinder.

1
Start by recalling Gauss's law, which states that the electric flux through a closed surface is proportional to the net charge enclosed within that surface. Mathematically, it is expressed as: ∮ E · dA = Q_enclosed / ε₀, where E is the electric field, dA is the infinitesimal area vector, Q_enclosed is the charge enclosed by the Gaussian surface, and ε₀ is the permittivity of free space.
To analyze the electric field inside the inner conductor of the cylindrical capacitor, consider a Gaussian surface that lies entirely within the material of the inner conductor. Since the inner conductor is a conductor, any excess charge resides on its outer surface, and the charge enclosed by this Gaussian surface is zero (Q_enclosed = 0).
Substitute Q_enclosed = 0 into Gauss's law: ∮ E · dA = 0 / ε₀. This implies that the electric flux through the Gaussian surface is zero. Since the Gaussian surface is arbitrary, the electric field E inside the inner conductor must be zero everywhere.
Next, consider the region outside the outer cylinder. Choose a cylindrical Gaussian surface that lies outside the outer cylinder. The outer cylinder is assumed to have a net charge that is balanced by the charge on the inner conductor, resulting in a net charge of zero for the entire system. Thus, Q_enclosed = 0 for this Gaussian surface as well.
Substitute Q_enclosed = 0 into Gauss's law for the region outside the outer cylinder: ∮ E · dA = 0 / ε₀. This again implies that the electric flux through the Gaussian surface is zero, and therefore, the electric field E outside the outer cylinder is also zero everywhere.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Gauss's Law
Gauss's Law states that the electric flux through a closed surface is proportional to the charge enclosed within that surface. Mathematically, it is expressed as Φ_E = Q_enc/ε₀, where Φ_E is the electric flux, Q_enc is the enclosed charge, and ε₀ is the permittivity of free space. This principle is fundamental in electrostatics for determining electric fields in symmetric charge distributions.
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Gauss' Law
Cylindrical Capacitor
A cylindrical capacitor consists of two concentric cylindrical conductors separated by an insulating material. The inner cylinder carries a charge, while the outer cylinder carries an equal and opposite charge. The electric field within and outside the capacitor can be analyzed using Gauss's Law, particularly in understanding how the field behaves in different regions of the capacitor.
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Capacitance of Cylindrical Capacitor
Electric Field Inside Conductors
In electrostatic equilibrium, the electric field inside a conductor is zero. This occurs because free charges within the conductor redistribute themselves in response to an external electric field until they reach a state where the internal field cancels out any applied field. This principle is crucial for understanding why the electric field is zero inside the inner conductor of a cylindrical capacitor.
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Electric Fields in Conductors
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