What is the line integral of between points i and f in FIGURE EX29.19?
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29. Sources of Magnetic Field
Ampere's Law (Calculus)
Problem 35
Textbook Question
Suppose the current in the coaxial cable of Problem 34, Fig. 28–45, is not uniformly distributed, but instead the current density j varies linearly with distance from the center: j1 = C1R for the inner conductor and j2 = C2R for the outer conductor. Each conductor still carries the same total current I0, in opposite directions. Determine the magnetic field in terms of I0 in the same four regions of space as in Problem 34.

1
Understand the problem: The current density in the coaxial cable varies linearly with distance from the center. The goal is to determine the magnetic field in four regions of space, using Ampère's law and the given current density distributions. The four regions are: (1) inside the inner conductor, (2) between the inner and outer conductors, (3) inside the outer conductor, and (4) outside the cable.
Step 1: Express the current density for the inner and outer conductors. The current density is given as j₁ = C₁R for the inner conductor and j₂ = C₂R for the outer conductor, where R is the radial distance from the center. The constants C₁ and C₂ can be determined by integrating the current density over the cross-sectional area of each conductor and equating it to the total current I₀.
Step 2: Calculate the magnetic field in region 1 (inside the inner conductor). Use Ampère's law, ∮B·dl = μ₀I_enclosed, where I_enclosed is the current enclosed within a radius r. To find I_enclosed, integrate the current density j₁ over the area of a circle of radius r. Substitute this into Ampère's law to solve for B.
Step 3: Calculate the magnetic field in region 2 (between the inner and outer conductors). In this region, the current enclosed is the total current I₀ carried by the inner conductor. Use Ampère's law directly, with I_enclosed = I₀, to find the magnetic field B as a function of r.
Step 4: Calculate the magnetic field in region 3 (inside the outer conductor). Similar to region 1, use Ampère's law and integrate the current density j₂ over the area of a circle of radius r to find the enclosed current. Be mindful that the current in the outer conductor flows in the opposite direction to the inner conductor. Substitute I_enclosed into Ampère's law to solve for B.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Current Density
Current density (j) is a vector quantity that represents the amount of electric current flowing per unit area of a conductor. In this problem, the current density varies linearly with the distance from the center of the coaxial cable, which means that the distribution of current is not uniform. Understanding how current density behaves in different regions is crucial for calculating the resulting magnetic field.
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Intro to Density
Ampère's Law
Ampère's Law relates the integrated magnetic field around a closed loop to the electric current passing through that loop. It is expressed mathematically as ∮B·dl = μ₀I_enc, where B is the magnetic field, dl is a differential length element, and I_enc is the enclosed current. This law is essential for determining the magnetic field in the coaxial cable, especially when the current distribution is non-uniform.
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Gauss' Law
Magnetic Field in Coaxial Cables
The magnetic field in coaxial cables can be analyzed in different regions: inside the inner conductor, between the conductors, outside the outer conductor, and within the outer conductor. Each region has distinct characteristics based on the current distribution and the application of Ampère's Law. Understanding these regions helps in calculating the magnetic field produced by the varying current densities in the conductors.
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Magnetic Fields and Magnetic Dipoles
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