(II) A child rolls a ball on a level floor 3.1 m to another child. If the ball makes 12.0 revolutions, what is its diameter?
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12. Rotational Kinematics
Rotational Position & Displacement
Problem 24b
Textbook Question
(II) A small rubber wheel is used to drive a large pottery wheel. The two wheels are mounted so that their circular edges touch. The small wheel has a radius of 2.0 cm and accelerates at the rate of 6.8 rad/s², and it is in contact with the pottery wheel (radius 27.0 cm) without slipping. Calculate the time it takes the pottery wheel to reach its required speed of 65 rpm.

1
Understand the problem: The small rubber wheel drives the larger pottery wheel through contact without slipping. This means the tangential velocities at the point of contact are equal. We are tasked with finding the time it takes for the pottery wheel to reach a speed of 65 rpm, given the angular acceleration of the small wheel.
Relate the angular velocities of the two wheels: Since the wheels are in contact without slipping, their tangential velocities are equal. The relationship between angular velocity (ω) and tangential velocity (v) is given by: . Therefore, , where and are the radii of the small and pottery wheels, respectively.
Convert the required speed of the pottery wheel to angular velocity: The pottery wheel's speed is given as 65 rpm. Convert this to radians per second using the formula: . This gives the target angular velocity of the pottery wheel in radians per second.
Determine the angular velocity of the small wheel: Using the relationship , solve for (the angular velocity of the small wheel) in terms of . Substitute the values of and to find when the pottery wheel reaches its target speed.
Calculate the time required: The small wheel starts from rest and accelerates at a constant rate of . Use the kinematic equation for angular motion: . Solve for by substituting the value of obtained in the previous step.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Angular Acceleration
Angular acceleration is the rate of change of angular velocity over time, typically measured in radians per second squared (rad/s²). In this scenario, the small rubber wheel has an angular acceleration of 6.8 rad/s², which affects how quickly it can increase its rotational speed. This concept is crucial for determining how the motion of the small wheel translates to the larger pottery wheel.
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Conservation of Angular Momentum
Relationship Between Linear and Angular Velocity
The relationship between linear velocity (v) and angular velocity (ω) is given by the equation v = rω, where r is the radius of the wheel. This relationship is essential for converting the angular speed of the small wheel into the linear speed at which it drives the larger pottery wheel. Understanding this concept allows us to calculate how the rotation of the small wheel influences the larger wheel's motion.
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Converting Between Linear & Rotational
Time to Reach a Specific Speed
To find the time it takes for an object to reach a specific speed, we can use the formula t = (ω_final - ω_initial) / α, where ω is angular velocity and α is angular acceleration. In this case, we need to convert the final speed of the pottery wheel from revolutions per minute (rpm) to radians per second to apply this formula effectively. This concept is key to solving the problem of how long it takes for the pottery wheel to reach its required speed.
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