A radio telescope, whose two antennas are separated by 55 m, is designed to receive 3.0-MHz radio waves produced by astronomical objects. The received radio waves create 3.0-MHz electronic signals in the telescope’s left and right antennas. These signals then travel by equal-length cables to a centrally located amplifier, where they are added together. The telescope can be “pointed” to a certain region of the sky by adding the instantaneous signal from the right antenna to a “time-delayed” signal received by the left antenna a time ∆t ago. (This time delay of the left signal can be easily accomplished with the proper electronic circuit.) If a radio astronomer wishes to “view” radio signals arriving from an object oriented at a 12° angle to the vertical as in Fig. 34–54, what time delay ∆t is necessary?
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34. Wave Optics
Diffraction
Problem 37
Textbook Question
Show that the radius r of the mᵗʰ dark Newton’s ring, as viewed from directly above (Fig. 34–18), is given by r = √mλR where R is the radius of curvature of the curved glass surface and λ is the wavelength of light used. Assume that the thickness of the air gap is much less than R at all points and that r ≪ R . [Hint: Use the binomial expansion.]

1
Start by understanding the setup: Newton's rings are formed due to the interference of light reflected from the top and bottom surfaces of the thin air film between a curved glass surface and a flat glass plate. The condition for destructive interference (dark rings) is that the optical path difference equals an odd multiple of half the wavelength.
The optical path difference for the mᵗʰ dark ring is given by: 2t = (m + 1/2)λ, where t is the thickness of the air film at the radius r, λ is the wavelength of light, and m is the ring number (m = 0, 1, 2, ...).
For small thickness t, the geometry of the curved surface gives the relationship: t ≈ r² / (2R), where r is the radius of the ring and R is the radius of curvature of the curved glass surface. Substitute this expression for t into the interference condition.
After substitution, the equation becomes: 2(r² / (2R)) = (m + 1/2)λ. Simplify this equation to isolate r², which gives: r² = mλR (neglecting the +1/2 term for large m, as it becomes negligible).
Finally, take the square root of both sides to solve for r: r = √(mλR). This is the desired expression for the radius of the mᵗʰ dark Newton's ring.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Newton's Rings
Newton's rings are a series of concentric circular interference patterns created by the reflection of light between a flat glass plate and a convex lens. The rings result from the varying thickness of the air gap between the two surfaces, leading to constructive and destructive interference of light waves. The radius of these rings can be mathematically related to the wavelength of light and the curvature of the lens.
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Interference of Light
Interference occurs when two or more light waves overlap and combine, resulting in a new wave pattern. This phenomenon can be constructive, where waves reinforce each other, or destructive, where they cancel each other out. The conditions for interference depend on the path difference between the waves, which is crucial for understanding the formation of Newton's rings.
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Binomial Expansion
The binomial expansion is a mathematical technique used to expand expressions that are raised to a power, particularly useful when dealing with approximations. In the context of Newton's rings, it allows for simplifying expressions involving the radius of curvature and the small thickness of the air gap. This simplification is essential for deriving the relationship between the radius of the mᵗʰ dark ring, the wavelength of light, and the radius of curvature.
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