To ensure that a ship is in stable equilibrium, would it be better if its center of buoyancy was above, below, or at the same point as its center of gravity? Explain.
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19. Fluid Mechanics
Buoyancy & Buoyant Force
Problem 90
Textbook Question
A tub of water rests on a scale as shown in Fig. 13–61. The weight of the tub plus water is 100 N. A 50-N concrete brick is tied by a cord to a fixed arm and lowered into the water but does not touch the bottom of the tub. What does the scale read now? [Hint: Draw two free-body diagrams, one for the brick and a second one for the tub + water + brick.]


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Step 1: Understand the problem. The tub of water initially weighs 100 N. A 50-N brick is submerged in the water but does not touch the bottom of the tub. The goal is to determine the new reading on the scale. The key concept here is buoyancy and how forces are distributed in the system.
Step 2: Analyze the forces acting on the brick. The brick experiences three forces: (1) its weight (50 N) acting downward, (2) the tension in the cord acting upward, and (3) the buoyant force exerted by the water acting upward. The buoyant force is equal to the weight of the water displaced by the brick, which can be calculated using Archimedes' principle.
Step 3: Analyze the forces acting on the tub + water + brick system. The scale measures the total downward force exerted on it. Initially, this force is 100 N (the weight of the tub and water). When the brick is submerged, the buoyant force exerted by the water on the brick creates an equal and opposite reaction force on the water, which increases the force on the scale.
Step 4: Relate the forces. The new reading on the scale will be the sum of the initial weight of the tub and water (100 N) and the buoyant force acting on the brick. The buoyant force can be calculated as \( F_b = \rho_{\text{water}} \cdot g \cdot V_{\text{brick}} \), where \( \rho_{\text{water}} \) is the density of water, \( g \) is the acceleration due to gravity, and \( V_{\text{brick}} \) is the volume of the brick.
Step 5: Conclude the calculation. Since the brick does not touch the bottom of the tub, its weight is not directly added to the scale reading. Instead, the scale reading increases only by the buoyant force. To find the final scale reading, add the buoyant force to the initial weight of the tub and water. This gives the new scale reading as \( 100 \text{ N} + F_b \).

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Buoyancy
Buoyancy is the upward force exerted by a fluid on an object submerged in it. This force counteracts the weight of the object, allowing it to float or remain suspended in the fluid. The magnitude of the buoyant force is equal to the weight of the fluid displaced by the object, as described by Archimedes' principle.
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Free-Body Diagram
A free-body diagram is a graphical representation used to visualize the forces acting on an object. It helps in identifying all the forces, including gravitational, normal, and tension forces, which are crucial for analyzing the motion and equilibrium of the object. In this scenario, drawing free-body diagrams for both the brick and the tub will clarify how the forces interact.
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Weight and Scale Readings
The weight of an object is the force exerted on it due to gravity, measured in newtons (N). A scale measures the total force acting on it, which includes the weight of the tub, water, and any additional forces from submerged objects. When the brick is submerged, the scale reading will change based on the buoyant force acting on the brick and how it affects the overall weight supported by the scale.
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