What is the magnetic flux through a loop when the loop is perpendicular to the magnetic field inside a solenoid?
When the loop is perpendicular to the magnetic field, the angle θ between the field and the normal to the surface is 0 degrees. The magnetic flux is given by Φ_B = B × A × cos(θ). Since cos(0°) = 1, the flux is Φ_B = B × A.