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Ch 16: Sound & Hearing
Young & Freedman Calc - University Physics 15th Edition
Young & Freedman Calc15th EditionUniversity PhysicsISBN: 9780135159552Not the one you use?Change textbook
Chapter 16, Problem 13

You are trying to overhear a juicy conversation, but from your distance of 15.0 m, it sounds like only an average whisper of 20.0 dB. How close should you move to the chatterboxes for the sound level to be 60.0 dB?

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1
Understand that sound intensity level in decibels (dB) is a logarithmic measure of the intensity of a sound relative to a reference level. The formula to convert intensity to decibels is: L=10log(IIref), where I is the intensity of the sound and Iref is the reference intensity.
Recognize that the intensity of sound decreases with distance according to the inverse square law: IPr2, where P is the power of the sound source and r is the distance from the source.
Set up the equation for the initial condition at 15.0 m with a sound level of 20.0 dB: 20=10log(IIref). Solve for I.
Set up the equation for the desired condition at a new distance r with a sound level of 60.0 dB: 60=10log(IIref). Solve for I.
Use the inverse square law to relate the two intensities and distances: IIref=r2r2. Solve for the new distance r.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Decibel Scale

The decibel (dB) scale is a logarithmic unit used to measure sound intensity. It quantifies sound levels relative to a reference level, typically the threshold of hearing. A change of 10 dB represents a tenfold change in intensity, making it crucial for understanding how sound levels increase or decrease with distance.
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Sound Intensity Level and the Decibel Scale

Inverse Square Law

The inverse square law states that the intensity of sound decreases with the square of the distance from the source. This principle is essential for calculating how sound intensity changes as you move closer or farther from the source, helping to determine the necessary distance to achieve a desired sound level.
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Sound Intensity and Distance

Sound intensity is the power per unit area carried by a sound wave. As you move closer to a sound source, the intensity increases, and the perceived loudness rises. Understanding the relationship between sound intensity and distance is key to solving problems involving changes in sound levels due to movement.
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Related Practice
Textbook Question

You live on a busy street, but as a music lover, you want to reduce the traffic noise. If you install special soundreflecting windows that reduce the sound intensity level (in dB) by 30 dB, by what fraction have you lowered the sound intensity (in W/m2)?

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Textbook Question

Sound is detected when a sound wave causes the tympanic membrane (the eardrum) to vibrate. Typically, the diameter of this membrane is about 8.4 mm in humans. How much energy is delivered to the eardrum each second when someone whispers (20 dB) a secret in your ear?

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Textbook Question

(a) By what factor must the sound intensity be increased to raise the sound intensity level by 13.0 dB? (b) Explain why you don't need to know the original sound intensity

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Textbook Question

An oscillator vibrating at 1250 Hz produces a sound wave that travels through an ideal gas at 325 m/s when the gas temperature is 22.0°C. For a certain experiment, you need to have the same oscillator produce sound of wavelength 28.5 cm in this gas. What should the gas temperature be to achieve this wavelength?

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Textbook Question

You live on a busy street, but as a music lover, you want to reduce the traffic noise. If, instead, you reduce the intensity by half, what change (in dB) do you make in the sound intensity level?

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Textbook Question

A sound wave in air at 20°C has a frequency of 320 Hz and a displacement amplitude of 5.00 × 10-3 mm. For this sound wave calculate the pressure amplitude (in Pa)

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