A quality control team collects a random sample of 3030 batteries and finds that the sample variance in battery life is 11.5611.56 $$hours^{2}. $$Assume the data are from a normally distributed population. Construct the 95%95\% confidence interval for the population variance and the population standard deviation.

For variance: (7.33,20.89)(7.33,20.89)For standard deviation: (2.71,4.57)(2.71,4.57)

For variance: (7.12,20.47)(7.12,20.47)For standard deviation: (2.71,4.57)(2.71,4.57)

For variance: (7.33,20.89)(7.33,20.89)For standard deviation: (2.28,4.11)(2.28,4.11)

For variance: (7.02,20.15)(7.02,20.15)For standard deviation: (2.03,4.54)(2.03,4.54)

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Determining the Minimum Sample Size Required
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8. Sampling Distributions & Confidence Intervals: Proportion

Confidence Intervals for Population Variance

8. Sampling Distributions & Confidence Intervals: Proportion

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Problem 13Multiple Choice

A quality control team collects a random sample of $30$ batteries and finds that the sample variance in battery life is $11.56$ hours². Assume the data are from a normally distributed population. Construct the $95 percent sign$ confidence interval for the population variance and the population standard deviation.

For variance: $open paren 7.12 comma 20.47 close paren$

For standard deviation: $open paren 2.71 comma 4.57 close paren$

For variance: $open paren 7.33 comma 20.89 close paren$

For standard deviation: $open paren 2.71 comma 4.57 close paren$

For variance: $open paren 7.33 comma 20.89 close paren$

For standard deviation: $open paren 2.28 comma 4.11 close paren$

For variance: $open paren 7.02 comma 20.15 close paren$

For standard deviation: $open paren 2.03 comma 4.54 close paren$

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