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Ch. 6 - Normal Probability Distributions
Triola - Elementary Statistics 14th Edition
Triola14th EditionElementary StatisticsISBN: 9780137366446Not the one you use?Change textbook
Chapter 6, Problem 6.4.9a

Ergonomics. Exercises 9–16 involve applications to ergonomics, as described in the Chapter Problem.


Safe Loading of Elevators The elevator in the car rental building at San Francisco International Airport has a placard stating that the maximum capacity is “4000 lb—27 passengers.” Because 4000/27=148, this converts to a mean passenger weight of 148 lb when the elevator is full. We will assume a worst-case scenario in which the elevator is filled with 27 adult males. Based on Data Set 1 “Body Data” in Appendix B, assume that adult males have weights that are normally distributed with a mean of 189 lb and a standard deviation of 39 lb.


a. Find the probability that 1 randomly selected adult male has a weight greater than 148 lb.

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Step 1: Identify the problem type. This is a probability problem involving a normal distribution. We are tasked with finding the probability that a randomly selected adult male has a weight greater than 148 lb.
Step 2: Standardize the value of 148 lb using the z-score formula. The z-score formula is given by: z=x-μσ, where x is the value of interest (148 lb), μ is the mean (189 lb), and σ is the standard deviation (39 lb). Plug in the values to calculate the z-score.
Step 3: Once the z-score is calculated, use the standard normal distribution table (or a statistical software) to find the cumulative probability corresponding to the z-score. This cumulative probability represents the probability that a randomly selected adult male has a weight less than 148 lb.
Step 4: To find the probability that a randomly selected adult male has a weight greater than 148 lb, subtract the cumulative probability from 1. This is because the total probability for a normal distribution is 1, and we are interested in the complement of the cumulative probability.
Step 5: Interpret the result. The final probability value will indicate the likelihood that a randomly selected adult male has a weight greater than 148 lb, based on the given normal distribution parameters.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Normal Distribution

Normal distribution is a probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean. In this context, the weights of adult males are assumed to follow a normal distribution with a specified mean and standard deviation, which allows us to calculate probabilities related to their weights.
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Finding Standard Normal Probabilities using z-Table

Z-Score

A Z-score is a statistical measurement that describes a value's relationship to the mean of a group of values. It is calculated by subtracting the mean from the value and then dividing by the standard deviation. In this problem, the Z-score will help determine how many standard deviations the weight of 148 lb is from the mean weight of adult males, facilitating the calculation of the probability that a randomly selected male weighs more than this value.
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Probability Calculation

Probability calculation involves determining the likelihood of a specific outcome occurring within a defined set of possibilities. In this scenario, we need to calculate the probability that a randomly selected adult male weighs more than 148 lb, which can be done using the Z-score and standard normal distribution tables or software to find the corresponding probability.
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Related Practice
Textbook Question

Ergonomics. Exercises 9–16 involve applications to ergonomics, as described in the Chapter Problem.


Aircraft Cockpit The overhead panel in an aircraft cockpit typically includes controls for such features as landing lights, fuel booster pumps, and oxygen. It is important for pilots to be able to reach those overhead controls while sitting. Seated adult males have overhead grip reaches that are normally distributed with a mean of 51.6 in. and a standard deviation of 2.2 in.


a. If an aircraft is designed for pilots with an overhead grip reach of 53 in., what percentage of adult males would not be able to reach the overhead controls? Is that percentage too high?

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Textbook Question

Using the Central Limit Theorem. In Exercises 5–8, assume that the amounts of weight that male college students gain during their freshman year are normally distributed with a mean of 1.2 kg and a standard deviation of 4.9 kg (based on Data Set 13 “Freshman 15” in Appendix B).


a. If 1 male college student is randomly selected, find the probability that he gains between 0.5 kg and 2.5 kg during freshman year.

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Textbook Question

Using the Central Limit Theorem. In Exercises 5–8, assume that the amounts of weight that male college students gain during their freshman year are normally distributed with a mean of 1.2 kg and a standard deviation of 4.9 kg (based on Data Set 13 “Freshman 15” in Appendix B).

a. If 1 male college student is randomly selected, find the probability that he gains between 0 kg and 3 kg during freshman year.

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Textbook Question

Transformations The heights (in inches) of women listed in Data Set 1 “Body Data” in Appendix B have a distribution that is approximately normal, so it appears that those heights are from a normally distributed population.


a. If 2 inches is added to each height, are the new heights also normally distributed?

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Textbook Question

Continuity Correction In testing the assumption that the probability of a baby boy is 0.512, a geneticist obtains a random sample of 1000 births and finds that 502 of them are boys. Using the continuity correction, describe the area under the graph of a normal distribution corresponding to the following. (For example, the area corresponding to “the probability of at least 502 boys” is this: the area to the right of 501.5.)


a. The probability of 502 or fewer boys

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Textbook Question

Mendelian Genetics When Mendel conducted his famous genetics experiments with peas, one sample of offspring consisted of 929 peas, with 705 of them having red flowers. If we assume, as Mendel did, that under these circumstances, there is a 3/4 probability that a pea will have a red flower, we would expect that 696.75 (or about 697) of the peas would have red flowers, so the result of 705 peas with red flowers is more than expected.


a. If Mendel’s assumed probability is correct, find the probability of getting 705 or more peas with red flowers.

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