In Exercises 52–53, use a right triangle to write each expression as an algebraic expression. Assume that x is positive and that the given inverse trigonometric function is defined for the expression in x. sec(sin⁻¹ 1/x)
Table of contents
- 0. Review of College Algebra4h 45m
- 1. Measuring Angles40m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
5. Inverse Trigonometric Functions and Basic Trigonometric Equations
Inverse Sine, Cosine, & Tangent
Problem 63
Textbook Question
In Exercises 63–82, use a sketch to find the exact value of each expression. cos (sin⁻¹ 4/5)
Verified step by step guidance1
Recognize that the expression is \( \cos(\sin^{-1}(\frac{4}{5})) \). Here, \( \sin^{-1}(\frac{4}{5}) \) represents an angle \( \theta \) whose sine is \( \frac{4}{5} \). So, let \( \theta = \sin^{-1}(\frac{4}{5}) \), which means \( \sin \theta = \frac{4}{5} \).
Draw a right triangle to represent the angle \( \theta \). Since \( \sin \theta = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{4}{5} \), label the side opposite to \( \theta \) as 4 and the hypotenuse as 5.
Use the Pythagorean theorem to find the adjacent side of the triangle. The formula is \( \text{adjacent} = \sqrt{\text{hypotenuse}^2 - \text{opposite}^2} = \sqrt{5^2 - 4^2} \).
Calculate the adjacent side length (do not simplify fully here, just set up the expression). This gives \( \sqrt{25 - 16} = \sqrt{9} \).
Now, find \( \cos \theta \) using the triangle sides: \( \cos \theta = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{\sqrt{9}}{5} \). This expression represents the exact value of \( \cos(\sin^{-1}(\frac{4}{5})) \).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Inverse Sine Function (sin⁻¹ or arcsin)
The inverse sine function, sin⁻¹(x), returns the angle whose sine is x. It is defined for inputs between -1 and 1 and outputs angles in the range [-π/2, π/2]. Understanding this helps identify the angle corresponding to a given sine value.
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Inverse Sine
Right Triangle Interpretation of Trigonometric Functions
Trigonometric functions can be represented using right triangles, where sine is the ratio of the opposite side to the hypotenuse. Sketching a triangle with sin θ = 4/5 allows determination of other sides and angles, facilitating calculation of related trig values like cosine.
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Introduction to Trigonometric Functions
Pythagorean Identity
The Pythagorean identity states that sin²θ + cos²θ = 1 for any angle θ. This relationship allows calculation of cosine when sine is known by rearranging to cos θ = ±√(1 - sin²θ), with the sign determined by the angle's quadrant.
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Pythagorean Identities
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