Solve the given quadratic equation by completing the square.
$x^2+3x-5=0$

$x=-$\frac$32,x=$\frac$52$

$x=-$\frac$32,x=$\sqrt{29}$$

$x=$\frac{-3+\sqrt{29}$}{2},x=$\frac{-3-\sqrt{29}$}{2}$

$x=$\frac{3+\sqrt{29}$}{2},x=$\frac{3-\sqrt{29}$}{2}$

Verified step by step guidance

Start with the quadratic equation: x^2 + 3x - 5 = 0.

Move the constant term to the other side of the equation: x^2 + 3x = 5.

To complete the square, take half of the coefficient of x, which is 3, divide it by 2 to get 3/2, and then square it to get (3/2)^2 = 9/4.

Add and subtract 9/4 inside the equation to maintain equality: x^2 + 3x + 9/4 - 9/4 = 5.

Rewrite the left side as a perfect square trinomial: (x + 3/2)^2 = 5 + 9/4, then solve for x by taking the square root of both sides and isolating x.

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Solve the given quadratic equation by completing the square. x2+3x−5=0x^2+3x-5=0x2+3x−5=0