In a circle with center and radius inches, if the measure of angle is , what is the length of minor arc ?
Table of contents
- 0. Review of College Algebra4h 45m
- 1. Measuring Angles40m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
2. Trigonometric Functions on Right Triangles
Trigonometric Functions on Right Triangles
Multiple Choice
Suppose is tangent to circle at point . If the distance from the center to point is units and the distance from to is units, what is the length of the radius of the circle?
A
units
B
units
C
units
D
units
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Verified step by step guidance1
Identify the given elements: line segment LK is tangent to circle J at point K, the distance from center J to point L is 10 units, and the distance from L to K is 6 units.
Recall the property that a radius drawn to a tangent point is perpendicular to the tangent line. Therefore, segment JK (the radius) is perpendicular to LK at point K.
Recognize that triangle JLK is a right triangle with right angle at K, where JK is the radius (unknown), LK is 6 units, and JL is 10 units.
Apply the Pythagorean theorem to triangle JLK: \(JL^2 = JK^2 + LK^2\), which translates to \$10^2 = r^2 + 6^2\(, where \)r$ is the radius JK.
Rearrange the equation to solve for the radius: \(r^2 = 10^2 - 6^2\), then express the radius as \(r = \sqrt{10^2 - 6^2}\).
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