Given triangle with sides , , opposite angles , , respectively, which of the following correctly expresses the Law of Sines?
Table of contents
- 0. Review of College Algebra4h 45m
- 1. Measuring Angles40m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
7. Non-Right Triangles
Law of Sines
Multiple Choice
Given the Law of Sines, could and be the side lengths of a triangle if and and the angle opposite is and the angle opposite is ?
A
No, because the sum of the angles is not .
B
Yes, because the Law of Sines is satisfied for these values.
C
Yes, because any two positive numbers can be side lengths of a triangle.
D
No, because the Law of Sines is not satisfied for these values.
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Verified step by step guidance1
Recall the Law of Sines formula: \(\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}\), where \(a\), \(b\), and \(c\) are side lengths opposite angles \(A\), \(B\), and \(C\) respectively.
Identify the given values: \(a = 3\), \(b = 7\), \(A = 80^\circ\), and \(B = 40^\circ\).
Calculate the ratio \(\frac{a}{\sin A}\) by substituting the known values: \(\frac{3}{\sin 80^\circ}\).
Calculate the ratio \(\frac{b}{\sin B}\) by substituting the known values: \(\frac{7}{\sin 40^\circ}\).
Compare the two ratios \(\frac{3}{\sin 80^\circ}\) and \(\frac{7}{\sin 40^\circ}\). If they are equal (or very close), the Law of Sines is satisfied and these could be side lengths of a triangle; if not, then these values cannot form a triangle according to the Law of Sines.
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