Determine the amplitude, period, and phase shift of each function. Then graph one period of the function. y = cos(x + π/2)
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Identify the general form of the cosine function: \(y = A \cos(B(x - C))\), where \(A\) is the amplitude, \(\frac{2\pi}{B}\) is the period, and \(C\) is the phase shift.
Rewrite the given function \(y = \cos(x + \frac{\pi}{2})\) in the form \(y = \cos(x - (-\frac{\pi}{2}))\) to clearly identify the phase shift.
Determine the amplitude \(A\) by looking at the coefficient in front of the cosine function. Here, since there is no coefficient, \(A = 1\).
Calculate the period using the formula \(\text{Period} = \frac{2\pi}{B}\). Since the coefficient of \(x\) is 1, \(B = 1\), so the period is \(2\pi\).
Find the phase shift \(C\) from the expression inside the cosine. Since it is \(x - (-\frac{\pi}{2})\), the phase shift is \(-\frac{\pi}{2}\), meaning the graph shifts to the left by \(\frac{\pi}{2}\) units.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Amplitude of a Trigonometric Function
Amplitude is the maximum absolute value of a trigonometric function, representing the height from the midline to the peak. For functions like y = cos(x), the amplitude is the coefficient before the cosine term. In y = cos(x + π/2), the amplitude is 1, since there is no coefficient other than 1.
The period is the length of one complete cycle of the function, calculated as 2π divided by the coefficient of x inside the function. For y = cos(bx + c), the period is 2π/|b|. In y = cos(x + π/2), since b = 1, the period remains 2π.
Phase shift is the horizontal translation of the graph, determined by solving (bx + c) = 0 for x. It equals -c/b, indicating how far the graph shifts left or right. For y = cos(x + π/2), the phase shift is -π/2, meaning the graph shifts π/2 units to the left.