Solve each problem. See Examples 3 and 4.The figure to the right indicates that the equation of a line passing through the point (a, 0) and making an angle θ with the x-axis is y = (tan θ) (x - a).Find an equation of the line passing through the point (5, 0) that makes an angle of 15° with the x-axis.

The slope of a line is a measure of its steepness, typically represented as 'm' in the slope-intercept form of a line equation, y = mx + b. In this context, the slope can be calculated using the tangent of the angle θ that the line makes with the x-axis, where m = tan(θ). This relationship is crucial for determining the direction of the line based on the given angle.

The point-slope form of a line is expressed as y - y₁ = m(x - x₁), where (x₁, y₁) is a point on the line and m is the slope. This form is particularly useful when you know a specific point through which the line passes and the slope. In the given problem, the point (5, 0) serves as (x₁, y₁), allowing us to apply this formula to find the equation of the line.

Trigonometric functions, such as sine, cosine, and tangent, relate the angles of a triangle to the lengths of its sides. In this problem, the tangent function is used to find the slope of the line based on the angle θ. Understanding how to apply these functions is essential for solving problems involving angles and their corresponding slopes in coordinate geometry.