Multiple Choice
Draw the structure of docosahexaenoic acid (22:6Δ4,7,10,13,16,19) and indicate what type of omega fatty acid it is.
10. Lipids
Omega-3 Fatty Acids
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Which of the following is a member of the omega-3 fatty acid family?
A
Oleic acid
B
Palmitic acid
C
Arachidonic acid
D
Eicosapentaenoic acid (EPA)
Verified step by step guidance1
Understand the concept of omega-3 fatty acids: Omega-3 fatty acids are a family of polyunsaturated fatty acids characterized by the presence of a double bond three carbons away from the methyl end (omega end) of the fatty acid chain.
Review the structure of each option: Oleic acid is a monounsaturated fatty acid with a single double bond, but it is not an omega-3 fatty acid. Palmitic acid is a saturated fatty acid with no double bonds, so it cannot be an omega-3 fatty acid. Arachidonic acid is a polyunsaturated fatty acid, but it belongs to the omega-6 family, not omega-3.
Identify the structure of Eicosapentaenoic acid (EPA): EPA is a polyunsaturated fatty acid with 20 carbons and 5 double bonds. Its first double bond is located three carbons away from the omega end, making it a member of the omega-3 family.
Relate the biological significance of EPA: EPA is an essential omega-3 fatty acid found in fish oil and is known for its anti-inflammatory properties and role in cardiovascular health.
Conclude that Eicosapentaenoic acid (EPA) is the correct answer based on its structural and functional characteristics as an omega-3 fatty acid.
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