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Multiple Choice
Which of the following best describes the chemical structure of an omega-3 fatty acid?
A
A polyunsaturated fatty acid with the first double bond at the third carbon from the methyl (omega) end
B
A saturated fatty acid with no double bonds
C
A polyunsaturated fatty acid with the first double bond at the sixth carbon from the methyl (omega) end
D
A monounsaturated fatty acid with a single double bond at the ninth carbon from the carboxyl end
Verified step by step guidance
1
Step 1: Understand the term 'omega-3 fatty acid'. Omega-3 fatty acids are a type of polyunsaturated fatty acid characterized by the position of the first double bond relative to the methyl (omega) end of the molecule.
Step 2: Recall the definition of 'polyunsaturated fatty acid'. These fatty acids contain more than one double bond in their hydrocarbon chain.
Step 3: Identify the 'methyl (omega) end' of the fatty acid. The omega end refers to the terminal carbon furthest from the carboxyl group (-COOH). Counting starts from this end to locate the position of the first double bond.
Step 4: Compare the options provided. The correct description of an omega-3 fatty acid is a polyunsaturated fatty acid with the first double bond at the third carbon from the methyl (omega) end.
Step 5: Eliminate incorrect options. A saturated fatty acid has no double bonds, a monounsaturated fatty acid has only one double bond, and an omega-6 fatty acid has the first double bond at the sixth carbon from the methyl end. These do not match the definition of an omega-3 fatty acid.