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Multiple Choice
Given the following data for an enzyme-catalyzed reaction:| [S] (mM) | Initial velocity ($v_0$) (μmol/min) ||----------|-----------------------------------|| 0.5 | 2.0 || 1.0 | 3.3 || 2.0 | 4.4 || 5.0 | 5.0 |What is the approximate $V_{max}$ for this enzyme under these conditions?
A
10.0 μmol/min
B
3.3 μmol/min
C
2.0 μmol/min
D
5.0 μmol/min
Verified step by step guidance
1
Step 1: Understand the concept of $V_{max}$. In enzyme kinetics, $V_{max}$ represents the maximum velocity of the reaction when the enzyme is saturated with substrate. It is the plateau of the Michaelis-Menten curve where increasing substrate concentration no longer increases the reaction rate.
Step 2: Analyze the data provided in the table. Look at the relationship between substrate concentration ([S]) and initial velocity ($v_0$). Notice that as [S] increases, $v_0$ approaches a maximum value.
Step 3: Identify the highest initial velocity ($v_0$) in the table. This value corresponds to the approximate $V_{max}$ because it represents the point where further increases in [S] do not significantly increase the reaction rate.
Step 4: Compare the given answer choices to the highest $v_0$ value in the table. The correct $V_{max}$ should match the highest observed velocity.
Step 5: Conclude that under these experimental conditions, the approximate $V_{max}$ is the highest $v_0$ value observed in the table, which is 5.0 μmol/min.