evaluate-sinh0sinhleft0right-given-the-definition-of-the-hyperbolic-sine-functio

Question

Evaluate ﻿sinh⁡(0)\sinh\left(0\right)sinh(0)﻿ given that the definition of the hyperbolic sine function is, ﻿sinh⁡(x)=ex−e−x2\sinh\left(x\right)=\frac{$$e^{x}$-e^{-x}$$}{2}sinh(x)=2ex−e−x​﻿, and sketch a plausible graph for ﻿y=sinh⁡(x)y=\sinh(x)y=sinh(x)﻿.

Accepted Answer

﻿sinh⁡(0)=0\sinh\left(0\right)=0sinh(0)=0﻿

Answer

﻿sinh⁡(0)=1\sinh\left(0\right)=1sinh(0)=1﻿

Answer

﻿sinh⁡(0)=−1\sinh\left(0\right)=-1sinh(0)=−1﻿

Evaluate sinh(0)\(\sinh\]\left\)(0\(\right\))sinh(0) given that the definition of the hyperbolic sine function is, sinh(x)=ex−e−x2\(\sinh\]\left\)(x\(\right\))=\(\frac{e^{x}\)-e^{-x}}{2}sinh(x)=2ex−e−x, and sketch a plausible graph for y=sinh(x)y=\(\sinh\)(x)y=sinh(x).

Evaluate $\(\sinh\]\left\)(0\(\right\))$ given that the definition of the hyperbolic sine function is, $\(\sinh\]\left\)(x\(\right\))=\(\frac{e^{x}\)-e^{-x}}{2}$ , and sketch a plausible graph for $y=\(\sinh\)(x)$ .