using-implicit-differentiation-what-is-the-dydxfracdydx-of-the-function-belowx3y

Question

Using implicit differentiation, what is the dydx\frac{dy}{dx} of the function below?x3+y3=$$15xyx^3$+y^3=15xy$$

Accepted Answer

dydx=5y−x2y2−5x\frac{dy}{dx}=\frac{$$5y-x^2$$}{$$y^2-5x$$}

Answer

dydx=15x2y3y2+x\frac{dy}{dx}=\frac{$$15x^2y$$}{$$3y^2+x$$}

Answer

dydx=−x2+32xy2\frac{dy}{dx}=-\frac{$$x^2+3$$}{$$2xy^2$$}

Answer

dydx=x2y−xy25\frac{dy}{dx}=\frac{$$x^2$y-xy^2$$}{5}

Using implicit differentiation, what is the dydx\(\frac{dy}{dx}\) of the function below?x3+y3=15xyx^3+y^3=15xy