the-first-derivative-of-a-continuous-function-gxgleftxright-is-gx2xx22gprimeleft

Question

The first derivative of a continuous function g(x)g\left(x\right) is g′(x)=2x(x−$$2)2g^{\prime}$$\left(x\right)=2x\left(x-2\$$right)^2. $$Find the second derivative of g(x)g\left(x\right) and sketch the general shape of its graph.

Accepted Answer

g′$$g^{\prime}$$′(x)=2(x−2)(3x−$$2)^{\prime}$$\left(x\right)=2\left(x-2\right)\left(3x-2\right)

Answer

g′$$g^{\prime}$$′(x)=4(x−2)(3x−$$2)^{\prime}$$\left(x\right)=4\left(x-2\right)\left(3x-2\right)

Answer

g′$$g^{\prime}$$′(x)=4(x−2)(3x−$$2)^{\prime}$$\left(x\right)=4\left(x-2\right)\left(3x-2\right)

The first derivative of a continuous function g(x)g\(\left\)(x\(\right\)) is g′(x)=2x(x−2)2g^{\(\prime\)}\(\left\)(x\(\right\))=2x\(\left\)(x-2\(\right\))^2. Find the second derivative of g(x)g\(\left\)(x\(\right\)) and sketch the general shape of its graph.

The first derivative of a continuous function $g (x)$ is $g^{'} (x) = 2 x {(x - 2)}^{2}$ . Find the second derivative of $g (x)$ and sketch the general shape of its graph.