determine-the-first-second-and-third-derivatives-of-the-function-gx4x37exgleftxr

Question

Determine the first, second, and third derivatives of the function g(x)=4x3+7exg\left(x\right)=$$4x^3$+7e^{x}.$$

Accepted Answer

g′(x)=$$12x2+7exg^{\prime}$$\left(x\right)=$$12x^2$+7e^{x}﻿g$$′$$g^{\prime}g$$′﻿﻿′(x)=^{\prime}\left(x\right)=′(x)=﻿ $$24x+7ex24x+7e^{x}﻿g$$′$$g^{\prime}g$$′﻿﻿′'′﻿﻿′(x)=^{\prime}\left(x\right)=′(x)=﻿ $$24+7ex24+7e^{x}$$

Answer

g′(x)=$$12x2+7exg^{\prime}$$\left(x\right)=$$12x^2$+7e^{x}g$$′$$g^{\prime}$$′(x)=^{\prime}\left(x\right)= $$24x+7ex24x+7e^{x}g$$′$$g^{\prime}$$﻿′'′﻿′(x)=^{\prime}\left(x\right)= $$48x+7ex48x+7e^{x}$$

Answer

g′(x)=$$12x2+7exg^{\prime}$$\left(x\right)=$$12x^2$+7e^{x}﻿g$$′$$g^{\prime}g$$′﻿﻿′(x)=^{\prime}\left(x\right)=′(x)=﻿ 24x+724x+7﻿g′$$g^{\prime}g$$′﻿﻿′'′﻿﻿′(x)=^{\prime}\left(x\right)=′(x)=﻿ 2424

Answer

g′(x)=$$12x2+7exg^{\prime}$$\left(x\right)=$$12x^2$+7e^{x}﻿g$$′$$g^{\prime}g$$′﻿﻿′(x)=^{\prime}\left(x\right)=′(x)=﻿ 24x+724x+7﻿g′$$g^{\prime}g$$′﻿﻿′'′﻿﻿′(x)=^{\prime}\left(x\right)=′(x)=﻿ 4848

Determine the first, second, and third derivatives of the function g(x)=4x3+7exg\(\left\)(x\(\right\))=4x^3+7e^{x}.

Determine the first, second, and third derivatives of the function $g (x) = 4 x^{3} + 7 e^{x}$ .