for-which-values-of-xx-is-the-equation-lnx24x4lnx22x1lnx22x12lnleftx2-4x4rightln

Question

For which values of xx is the equation ln⁡(x2−4x+4)+ln⁡(x2+2x+1)=ln⁡((x−2)2(x+1)2)\ln\$$left(x^2-4x+4$$\right)+\ln\$$left(x^2+2x+1$$\right)=\ln\left(\left(x-2\$$right)^2$$\left(x+1\$$right)^2$$\right) true?

Accepted Answer

x∈R\{−1,2}x\in\mathbb{R}\backslash\left\lbrace-1,2\right\rbrace

Answer

x∈R\{−2,−1}x\in\mathbb{R}\backslash\left\lbrace-2,-1\right\rbrace

Answer

x∈R\{1,2}x\in\mathbb{R}\backslash\left\lbrace1,2\right\rbrace

Answer

x∈R\{−2,1}x\in\mathbb{R}\backslash\left\lbrace-2,1\right\rbrace

For which values of xx is the equation ln(x2−4x+4)+ln(x2+2x+1)=ln((x−2)2(x+1)2)\(\ln\]\left\)(x^2-4x+4\(\right\))+\(\ln\[\left\)(x^2+2x+1\(\right\))=\(\ln\]\left\)(\(\left\)(x-2\(\right\))^2\(\left\)(x+1\(\right\))^2\(\right\)) true?

For which values of $x$ is the equation $\ln (x^{2} - 4 x + 4) + \ln (x^{2} + 2 x + 1) = \ln ({(x - 2)}^{2} {(x + 1)}^{2})$ true?