Determine the rate of change of the radius of a soap bubble if its volume increases at a rate of $20{\text{ cm}}^3\text{/min}$. The radius of the bubble is $5\text{ cm}$.

$\frac{dr}{dt}=-\frac{1}{10\pi }\text{cm/min}$

$\frac{dr}{dt}=\frac{1}{10\pi }\text{cm/min}$

$\frac{dr}{dt}=-\frac{1}{5\pi }\text{cm/min}$

$\(\frac{dr}{dt}\) = \(\frac{1}{5 \pi}\) \, \(\text{cm/min}\)$