what-is-the-derivative-of-the-following-functionq4x2qsqrt4-x2

Question

What is the derivative of the following function?q=4−x2q=\sqrt{$$4-x^2$$}

Accepted Answer

dqdx=−x4−x2\frac{dq}{dx}=-\frac{x}{\sqrt{$$4-x^2$$}}

Answer

dqdx=x2−4(x+2)2\frac{dq}{dx}=\frac{$$x^2-4$$}{\left(x+2\$$right)^2$$}

Answer

dqdx=4x4+x2x2−2\frac{dq}{dx}=\frac{4x\sqrt{$$4+x^2$$}}{$$x^2-2$$}

Answer

dqdx=x2+4x+5\frac{dq}{dx}=$$x^2+4x+5$$

What is the derivative of the following function?q=4−x2q=\(\sqrt{4-x^2}\)