letpa14pa34pba35pafrac14paprimefrac34pbafrac35-and-pba12pbaprimefrac12-what-is-p

Question

Let $P (A) = \frac{1}{4}, P (A^{'}) = \frac{3}{4}, P (B ∣ A) = \frac{3}{5},$ and $P (B ∣ A^{'}) = \frac{1}{2}$ . What is $P (A ∣ B)$ according to Bayes’ Theorem?

Accepted Answer

$\frac{2}{7}$

Answer

$\frac{2}{7}$

Answer

$\frac{2}{7}$

Answer

$\frac{2}{7}$

Let P(A)=14,P(A′)=34,P(B∣A)=35,P(A)=\frac14,P(A^{\prime})=\frac34,P(B|A)=\frac35, and P(B∣A′)=12P(B|A^{\prime})=\frac{1}{2}. What is P(A∣B) P(A|B) according to Bayes’ Theorem?

Let $P (A) = \frac{1}{4}, P (A^{'}) = \frac{3}{4}, P (B ∣ A) = \frac{3}{5},$ and $P (B ∣ A^{'}) = \frac{1}{2}$ . What is $P (A ∣ B)$ according to Bayes’ Theorem?