a-researcher-wants-to-estimate-the-difference-in-proportions-of-two-populations-

Question

A researcher wants to estimate the difference in proportions of two populations. In sample $1$ , $x sub 1 equals 52$ successes out of $n sub 1 equals 220$ . In sample $2$ , $x sub 2 equals 41$ successes out of $n sub 2 equals 180$ . Construct a $90 percent sign$ confidence interval for $p sub 1 minus p sub 2$ .

Accepted Answer

$open paren negative 0.0611 comma 0.0783 close paren$

Answer

$open paren negative 0.0611 comma 0.0783 close paren$

Answer

$open paren negative 0.0611 comma 0.0783 close paren$

Answer

$open paren negative 0.0611 comma 0.0783 close paren$

A researcher wants to estimate the difference in proportions of two populations. In sample 11, x1=52 x_1 = 52 successes out of n1=220 n_1 = 220 . In sample 22, x2=41 x_2 = 41 successes out of n2=180 n_2 = 180 . Construct a 90%90\% confidence interval for p1−p2p_1-p_2.